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swat32
3 years ago
13

The moon is about 240,000 miles from Earth. What is the distance written as a whole number multiplied by a power of ten?

Mathematics
1 answer:
iVinArrow [24]3 years ago
4 0
I think it equals 2,40,000
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2350 million in standard form
topjm [15]

Answer:

in this problem we have

2,350 million

Remember that

1 million=1,000,000

so

2,350 million=2,350*1,000,000=2,350,000,000

convert to standard form

2,350,000,000=2.35*10^{9}

therefore

the answer is

2.35*10^{9}

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
A store finds that its sales revenue changes at a rate given by S'(t) = −30t2 + 420t dollars per day where t is the number of da
allochka39001 [22]

Answer:

Step-by-step explanation:

Give the rate of change of sales revenue of a store modeled by the equation S'(t)= -30t^{2} + 420t. The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

\int\limits {S'(t)} \, dt = \int\limits ({-30t^{2}+420t }) \, dt \\S(t) = \frac{-30t^{3} }{3}+\frac{420t^{2} }{2}\\  S(t)= -10t^{3} +210t^{2} \\

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;

Given\ S(t) = -10t^{3} + 210t^{2}

S(0) = -10(0)^{3} + 210(0)^{2}\\S(0) = 0\\S(7) = -10(7)^{3} + 210(7)^{2}\\S(7) = -3430+10,290\\S(7) = 6,860

Total sales = S(7) - S(0)

= 6,860 - 0

Total sales for the first week = $6,860

b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;

Total sales for the second week = S(14)-S(7)

Given S(7) = 6,860

To get S(14);

S(14) = -10(14)^{3} + 210(14)^{2}\\S(14) = -27,440+41,160\\S(14) = 13,720

The total sales for the second week after campaign ends = 13,720 - 6,860

= $6,860

8 0
3 years ago
PLEASE HELP THIS IS URGENT! IM REALLY CONFUSED ON THIS AND I REALLY NEED HELP AND AN EXPLANATION ON THIS!! PLEASE AND THANK YOU!
FromTheMoon [43]

Answer:

A is 7   and B is

Step-by-step explanation:

A: 3x2 is 6+1 is 7

B: 3x5 is 8 + 1 so 9+9+9+9 is 36

8 0
3 years ago
There are eight girls competing in an ice-skating competition. In how many ways can they finish in first, second, and third plac
docker41 [41]
Since we need to find the number of ways they could enter first, second and third place, (I can't demonstrate, but you should get the idea) take 8, 7 and 6 and multiply them, 5-1 we don't need, we just need 8, 7, and 6, multiply those three numbers and you get 336, there you go, 336 ways to organize all 8 girls in first, second and third place, hope this helps
7 0
4 years ago
1)Make an area model(Table) or a tree diagram to model all the possible combinations in this situation. 2)What is the theoretica
Ann [662]

Answer:

Example:

A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.

a) Construct a probability tree of the problem.

b) Calculate the probability that Paul picks:

i) two black balls

ii) a black ball in his second draw

Solution:

tree diagram

a) Check that the probabilities in the last column add up to 1.

b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.

ii) There are two outcomes where the second ball can be black.

Either (B, B) or (W, B)

From the probability tree diagram, we get:

P(second ball black)

= P(B, B) or P(W, B)

= P(B, B) + P(W, B)

6 0
3 years ago
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