Answer:
in this problem we have
2,350 million
Remember that
1 million=1,000,000
so
2,350 million=2,350*1,000,000=2,350,000,000
convert to standard form
2,350,000,000=2.35*10^{9}
therefore
the answer is
2.35*10^{9}
Step-by-step explanation:
Answer:
Step-by-step explanation:
Give the rate of change of sales revenue of a store modeled by the equation
. The Total sales revenue function S(t) can be gotten by integrating the function given as shown;

a) The total sales for the first week after the campaign ends (t = 0 to t = 7) is expressed as shown;


Total sales = S(7) - S(0)
= 6,860 - 0
Total sales for the first week = $6,860
b) The total sales for the secondweek after the campaign ends (t = 7 to t = 14) is expressed as shown;
Total sales for the second week = S(14)-S(7)
Given S(7) = 6,860
To get S(14);

The total sales for the second week after campaign ends = 13,720 - 6,860
= $6,860
Answer:
A is 7 and B is
Step-by-step explanation:
A: 3x2 is 6+1 is 7
B: 3x5 is 8 + 1 so 9+9+9+9 is 36
Since we need to find the number of ways they could enter first, second and third place, (I can't demonstrate, but you should get the idea) take 8, 7 and 6 and multiply them, 5-1 we don't need, we just need 8, 7, and 6, multiply those three numbers and you get 336, there you go, 336 ways to organize all 8 girls in first, second and third place, hope this helps
Answer:
Example:
A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.
a) Construct a probability tree of the problem.
b) Calculate the probability that Paul picks:
i) two black balls
ii) a black ball in his second draw
Solution:
tree diagram
a) Check that the probabilities in the last column add up to 1.
b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.
ii) There are two outcomes where the second ball can be black.
Either (B, B) or (W, B)
From the probability tree diagram, we get:
P(second ball black)
= P(B, B) or P(W, B)
= P(B, B) + P(W, B)