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3 years ago

5

Solve the proportion 7/5=21/x

1 answer:

Rus_ich [418]3 years ago

8 0

If you’re asking what x equals, the answer is 15

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Help me do question 9 and 10 I am 6th grade. Please

Phoenix [80]

Answer:

Step-by-step explanation:

9 - ratio 3:5

10 1/8 + 1/4 = 1/8 + 2/8 = 3/8 of the pizza eaten

so 5/8th of the pizza is left

8 0

3 years ago

What is 5(4x+7)=295 it is an equation

frutty [35]

Divide both sides by 5

4x + 7 = 59

Subtract 7 on both sides

4x = 52

Divide 4 on both sides

x = 13

3 0

3 years ago

EXTRA POINTS: PLZ HELP

kvasek [131]

I think that
Every point is moved so that it is 2/3 as far from the y axis
should be the answer

6 0

3 years ago

Which of the following are solutions to the equation below?

scoundrel [369]

Answer:

The correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Step-by-step explanation:

Given the expression

$x^2+10x+25=8$

Subtract 25 from both sides

$x^2+10x+25-25=8-25$

Simplify

$x^2+10x=-17$

Add 25 or 5² to both sides

$x^2+10x+5^2=8$

as

$x^2+10x+5^2=\left(x+5\right)^2$

so the expression becomes

$\left(x+5\right)^2=8$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x+5=\sqrt{8}$

Subtract 5 from both sides

$x+5-5=2\sqrt{2}-5$

$x=2\sqrt{2}-5$

solve

$x+5=-\sqrt{8}$

Subtract 5 from both sides

$x+5-5=-2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

Therefore, the solution to the equation

$x=2\sqrt{2}-5,\:x=-2\sqrt{2}-5$

Hence, the correct options for the solution values are:

$x=2\sqrt{2}-5$

$x=-2\sqrt{2}-5$

6 0

3 years ago

Line BC is tangent to the circle centered at A. Find the measure of angle BCA. Explain or show your reasoning.

Virty [35]

Answer:

$m\angle BCA= 33\degree$

Step-by-step explanation:

$In\: \odot A$ BC is tangent to the circle at point B.

Therefore, by tangent-radius theorem:

$\therefore AB\perp BC$

$\therefore \angle ABC = 90\degree$

$In\: \triangle ABC,$

$m\angle ABC +m\angle BAC +m\angle BCA= 180\degree$

$90\degree+57\degree +m\angle BCA= 180\degree$

$147\degree +m\angle BCA= 180\degree$

$m\angle BCA= 180\degree - 147\degree$

$m\angle BCA= 33\degree$

4 0

2 years ago