Answer:
14x-21%
Step-by-step explanation:
it comes easy
5(2x-8)+15=-15
10x-40+15=-15
10x-25=-15
10x=10
x=1
Answer:
Part A) The surface area of prism B is equal to the surface area of prism A multiplied by the scale factor (m) squared
Part B) The Volume of prism B is equal to the Volume of prism A multiplied by the scale factor (m) elevated to the cube
Step-by-step explanation:
Part A) we know that
The scale factor is equal to m
The surface area of the prism is equal to

where
B is the area of the base
P is the perimeter of the base
h is the height of the prism
we have
Prism A



substitute
![SA=[2(xy)+2(x+y)z]\ units^{2}](https://tex.z-dn.net/?f=SA%3D%5B2%28xy%29%2B2%28x%2By%29z%5D%5C%20units%5E%7B2%7D)
Prism B



substitute
![SB=[2(xym^{2})+2m(x+y)mz]\ units^{2}](https://tex.z-dn.net/?f=SB%3D%5B2%28xym%5E%7B2%7D%29%2B2m%28x%2By%29mz%5D%5C%20units%5E%7B2%7D)
![SB=[2(xym^{2})+2m^{2}(x+y)z]\ units^{2}](https://tex.z-dn.net/?f=SB%3D%5B2%28xym%5E%7B2%7D%29%2B2m%5E%7B2%7D%28x%2By%29z%5D%5C%20units%5E%7B2%7D)
therefore
The surface area of prism B is equal to the surface area of prism A multiplied by the scale factor (m) squared
Part B) we know that
The volume of the prism is equal to

where
B is the area of the base
h is the height of the prism
we have
Prism A


substitute
![VA=[(xyz]\ units^{3}](https://tex.z-dn.net/?f=VA%3D%5B%28xyz%5D%5C%20units%5E%7B3%7D)
Prism B


substitute
![VB=[(xym^{2})mz]\ units^{3}](https://tex.z-dn.net/?f=VB%3D%5B%28xym%5E%7B2%7D%29mz%5D%5C%20units%5E%7B3%7D)
![VB=[(xyzm^{3})]\ units^{3}](https://tex.z-dn.net/?f=VB%3D%5B%28xyzm%5E%7B3%7D%29%5D%5C%20units%5E%7B3%7D)
therefore
The Volume of prism B is equal to the Volume of prism A multiplied by the scale factor (m) elevated to the cube
Answer: 3
Step-by-step explanation:
Since 6 + 6 is 12 so 3 + 3 is 6 and 12 + 6 is 18 and you multiply each side by two
Subtract 52 from m, s, and the total amount of students.. 52 is the amount of students that would take both math and science. m now equals 43, s now equals 23, and the total students remaining is 95.
Since the criteria wants you to exclude students that take math or science, add m and s together.

This is the total amount of students that take math or science.
To find the probability of picking a student that doesn't take math or science, subtract 66 from the total amount of students.

Take this amount and divide by the total amount of students again.

Convert the decimal into a percentage.

%
There is a
30.52% chance of picking a student that doesn't take math nor science.