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Alina [70]
3 years ago
6

Combining transformations result in interesting designs. True False

Mathematics
1 answer:
aev [14]3 years ago
7 0
True is the correct answer Hope this helped =)
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Tommy will spend start fraction, 1/5 of his time this weekend studying for his 4 final exams. What fraction of the weekend will
maxonik [38]

Answer:

1/20

Step-by-step explanation:

(1/5) ÷ 4

*remember, you don't divide fractions, you multiply the first fraction by the inverse (flip it upside down) of the second fraction.*

(1/5) × (1/4) = (1/20)

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3 years ago
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9100 dollard placed into an account with an annual intrest of 5% to the neareast year how long will it take for the account to v
shusha [124]

Answer:

81 years

Step-by-step explanation:

The answer is 81 because 5% of 9100 is 455 and 36900 divided by 455 is rounded to 81.

4 0
3 years ago
Which term is defined as a fee charged for the use of money?
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Which term is defined as a fee charged for the use of money?

\sf\purple{a.\:interest} ✔

b. down payment

C. principal

d. default

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Interest is defined as a fee charge for the use of money.

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35\:ヅ}}}}}

8 0
2 years ago
If a bus can travel 194 miles in 4 hours how many miles can it travel in 1 hour l
Oksana_A [137]
In 1 hr the bus would have traveled 48.5 miles

7 0
3 years ago
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One positive number is one-fifth of another number. the difference of the two numbers is 84. find the numbers.
seraphim [82]
Answer:  The numbers are:  " 21 " and " 105 " .
___________________________________________________
Explanation:
___________________________________________________
Let "x" be the "one positive number:

Let "y" be the "[an]othyer number".

x = 1/5 (y)
___________________________________________________
Given that the difference of the two number is "84" ;  and that "x" is (1/5) of  "y" ;  we determine that "x" is smaller than "y".

So, y − x = 84 .

Add "x" to each side of this equation; to solve for "y" in terms of "x" ;

y − x + x = 84 + x  ;

 y = 84 + x ;
___________________________________________________
So, we have: 

 x = (1/5) y ;

and:  y = 84 + x  ;

Substitute "(1/5)y" for "x" ;  in  "y = 84 + x " ;  to solve for "y" ;

 y = 84 + [ (1/5)y ]

Subtract  " [ (1/5)y ] " from EACH SIDE of the equation ;

y − [ (1/5)y ] = 84 + [ (1/5)y ] −  [ (1/5)y ]  ;

to get:

  [ (4/5)y ] = 84 ;


       ↔    (4y) / 5 = 84  ;
      
        →  4y = 5 * 84  ;

      Divide EACH SIDE of the equation by "4" ; 
to isolate "y" on one side of the equation; and to solve for "y" ;

           4y / 4 = (5 * 84) / 4 ;

                 y =  5 * (84/4) = 5 * 21 = 105 .

   y = 105 .
___________________________________________________
Now, plug "105" for "y" into:
___________________________________________________
Either:
___________________________________________________
 x = (1/5) y ;

OR:

  y = 84 + x  ;
___________________________________________________
to solve for "x" ;
___________________________________________________
Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
___________________________________________________
Start with:

x = (1/5)y 

    →  (1/5)*(105) = 105 / 5 = 21 ;  x = 21 ; 

___________________________________________________
So, x = 21;  y = 105 .
___________________________________________________
Now, let us see if this values hold true in the other equation:
___________________________________________________
y = 84 + x ;

105 = ? 84 + 21 ?
 
105 = ? 105 ? Yes!
___________________________________________________
The numbers are:  " 21 " and  "105 " .
___________________________________________________

6 0
3 years ago
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