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Lina20 [59]
3 years ago
5

A computer can be classified as either cutting dash edge or ancient. Suppose that 99​% of computers are classified as ancient.​(

a) Two computers are chosen at random. What is the probability that both computers are ancient​?​(b) Five computers are chosen at random. What is the probability that all five computers are ancient​?​(c) What is the probability that at least one of five randomly selected computers is cutting dash edge​? Would it be unusual that at least one of five randomly selected computers is cutting dash edge​?
Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0

Answer:

Step-by-step explanation:

a )

probability of a computer being ancient = .99

probability of a computer being cutting-edge =.01

probability of two selected  computer being old

= .99 x .99

= .98 or 98%

b )

probability of 5 selected computers being old

= .99 x .99 x .99 x .99 x .99

= .95 or 95%

c )

probability that at least one of the five selected computers is cutting-edge

= 1 - probability of 5 selected computers being old

= 1 - .95

= .05

5 %

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71

Step-by-step explanation:

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To find the missing angle:

180 - 90 = 90

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People were asked how many children are in their family. The results are shown below. How many people were surveyed?
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19 people were surveyed

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Into the boxes:<br> 2x + 8 = 1x + 9<br> Solve the equation.
JulsSmile [24]

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3 years ago
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An airline's public relations department claims that when luggage is lost, 88% is recovered and delivered to its owner within 24
melisa1 [442]

Answer:

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

Step-by-step explanation:

Test if the proportion of times that luggage is returned within 24 hours is less than 0. 88

At the null hypothesis, we test if the proportion is of 0.88, that is:

H_0: p = 0.88

At the alternate hypothesis, we test if this proportion is less than 0.88, that is:

H_a: p < 0.88

The hypothesis statements are: H0: p = 0.88 versus HA : p < 0.88

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.88 is tested at the null hypothesis:

This means that \mu = 0.88, \sigma = \sqrt{0.88*0.12}

A consumer group who surveyed a large number of air travelers found that 138 out of 160 people who lost luggage on that airline were reunited with the missing items by the next day.

This means that n = 160, X = \frac{138}{160} = 0.8625

Test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.8625 - 0.88}{\frac{\sqrt{0.88*0.12}}{\sqrt{160}}}

z = -0.68

P-value of the test:

The p-value of the test is the probability of finding a sample proportion below 0.8625, which is the p-value of z = -0.68.

Looking at the z-table, the p-value of z = -0.68 is of 0.2483.

The p-value of the test is 0.2483 > 0.1, which means that the data does not provide sufficient evidence to conclude that the proportion of times that luggage is returned within 24 hours is less than 0.88.

7 0
2 years ago
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(I assume the two different name things, isaac&dominic, is a mistake since there isnt any information for Dominic)

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