Answer:
Albert invested $21,000
John invested $49,000
Step-by-step explanation:
First add 3 and 7
3+7=10
Now divide 70,000 by 10
70,000/10=7000
Now multiply 7000 by 3 and 7
7000x3=21,000
7000x7=49,000
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Answer: 1.
x |0|0.5|2
dy/dx |2|5 |undefined
2.
x |0 |0.5| 2
dy/dx |undefined|5 | 2
3.
x | 0 |0.5|2
dy/dx|undefined |4 |2
1. solution,
length of rectangle A(l)=3.1units
breadth of rectangle A(b)=1units
now,
area of rectangle A=l×b
=3.1units×1units
=3.1 sq units
2.solution,
length of rectangle B(l)=3.1units
breadth of rectangle B (b)=0.4units
area of rectangleB=l×b
=3.1units×0.4units
=1.24 sq units
3.solution,
length=3.1units
breadth=1.4units
area =lxb
=3.1units x 1.4units
=4.34units
.
If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is .
Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)
Hence, β = - 3 and α + a = 1 and α - a = -3
Now, solving those two equations of α and a we get,
2α = - 2, ⇒ α = -1 and
a = 1 - α = 2.
Now, eccentricity of the hyperbola is given by {Since given}
Therefore, the equation of the given hyperbola will be
. (Answer)
The equation of the line in the point-slope form is y - 15 = (x - 10)
The point-slope form of a linear equation is , where
∵ Point A = (10 , 15)
∵ The x-coordinate of the second point is 125% of x-coordinate
of point A
∴ x-coordinate of second point = × 10
∴ x-coordinate of second point = 12.5
∵ The y-coordinate of the second point is 75% of y-coordinate
∴ y-coordinate of second point = × 15
∴ y-coordinate of second point = 11.25
∴ The coordinates of the second point are (12.5 , 11.25)
Let us find the slope of the line by using the rule of it above
∵ = (10 , 15)
∵ = (12.5 , 11.25)
∴
Now we can write the equation
∵ The point-slope form is
∵
- Substitute these values in the form of the equation
∴ y - 15 = (x - 10)
Learn more:
You can learn more about the linear equation in brainly.com/question/4152194
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35 combinations of a starter and a main course.
1a, 1b, 1c, 1d, 1e, 1f, 1g
2a, 2b, 2c, 2d, 2e, 2f, 2g
3a, 3b, 3c, 3d, 3e, 3f, 3g
4a, 4b, 4c, 4d, 4e, 4f, 4g
5a, 5b, 5c, 5d, 5e, 5f, 5g
i hope this helps