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Licemer1 [7]
3 years ago
10

Albert and John are partners in a Bakery store. They needed $70,000 to start the business. They

Mathematics
2 answers:
Ratling [72]3 years ago
6 0

Answer:

Albert invested $21,000

John invested $49,000

Step-by-step explanation:

First add 3 and 7

3+7=10

Now divide 70,000 by 10

70,000/10=7000

Now multiply 7000 by 3 and 7

7000x3=21,000

7000x7=49,000

Hope this helps! Plz award Brainliest : )

viktelen [127]3 years ago
3 0
$30,000 you’re welcome
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Choose the appropriate table for the differential equation dy/dx=x+1/x
kenny6666 [7]

Answer: 1.

x |0|0.5|2

dy/dx |2|5 |undefined

2.

x |0 |0.5| 2

dy/dx |undefined|5 | 2

3.

x | 0 |0.5|2

dy/dx|undefined |4 |2

Step-by-step explanation:

7 0
2 years ago
Here is a diagram that represents (3.1) ⋅ (1.4).
Firdavs [7]

Step-by-step explanation:

1. solution,

length of rectangle A(l)=3.1units

breadth of rectangle A(b)=1units

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area of rectangle A=l×b

=3.1units×1units

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2.solution,

length of rectangle B(l)=3.1units

breadth of rectangle B (b)=0.4units

now,

area of rectangleB=l×b

=3.1units×0.4units

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3.solution,

length=3.1units

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4 0
3 years ago
Read 2 more answers
the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2
Ksivusya [100]

Answer:

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1.

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is \frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1.

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,  

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by b^{2} = a^{2}(e^{2}  - 1) = 4[(\frac{5}{2} )^{2} -1] = 21 {Since e = \frac{5}{2} given}

Therefore, the equation of the given hyperbola will be  

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1. (Answer)

6 0
3 years ago
A line passes through point A(10,15). A second point on the line has an x-value that is 125% of the x-value of point A and a y-v
melisa1 [442]

The equation of the line in the point-slope form is y - 15 = -\frac{3}{2} (x - 10)

Step-by-step explanation:

The point-slope form of a linear equation is y-y_{1}=m(x-x_{1}) , where

  • m is the slope of the line, where m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} , (x_{1},y_{1}) and (x_{2},y_{2}) are two points on the line
  • (x_{1},y_{1}) is a point on the line

∵ Point A = (10 , 15)

∵ The x-coordinate of the second point is 125% of x-coordinate

  of point A

∴ x-coordinate of second point = \frac{125}{100} × 10

∴ x-coordinate of second point = 12.5

∵ The y-coordinate of the second point is 75% of y-coordinate

  of point A

∴ y-coordinate of second point = \frac{75}{100} × 15

∴ y-coordinate of second point = 11.25

∴ The coordinates of the second point are (12.5 , 11.25)

Let us find the slope of the line by using the rule of it above

∵ (x_{1},y_{1}) = (10 , 15)

∵ (x_{2},y_{2}) = (12.5 , 11.25)

∴ m=\frac{11.25-15}{12.5-10}=\frac{-3.75}{2.5}=-\frac{3}{2}

Now we can write the equation

∵ The point-slope form is y-y_{1}=m(x-x_{1})

∵ m=-\frac{3}{2}

∵ (x_{1},y_{1}) = (10 , 15)

- Substitute these values in the form of the equation

∴ y - 15 = -\frac{3}{2} (x - 10)

The equation of the line in the point-slope form is y - 15 = -\frac{3}{2} (x - 10)

Learn more:

You can learn more about the linear equation in brainly.com/question/4152194

#LearnwithBrainly

5 0
3 years ago
jo goes to a restaurant for a meal. there are 5 starters and 7 main courses to choose from. Jo chooses a starter and a main cour
saveliy_v [14]

Answer:

35 combinations of a starter and a main course.

Step-by-step explanation:

1a, 1b, 1c, 1d, 1e, 1f, 1g

2a, 2b, 2c, 2d, 2e, 2f, 2g

3a, 3b, 3c, 3d, 3e, 3f, 3g

4a, 4b, 4c, 4d, 4e, 4f, 4g

5a, 5b, 5c, 5d, 5e, 5f, 5g

i hope this helps

7 0
3 years ago
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