z=xm+n-p
We need to isolate x to one side I will do that on the left side so it looks cleaner, therefore I will first flip the equation.
xm+n-p=z
Now move the n and p to the right side
xm=z-n+p
x=(z-n+p)/m
Hope this helped, if you have any questions about this just comment and I will come answer.
Answer:

The domain for x is all real numbers greater than zero and less than 5 com
Step-by-step explanation:
<em><u>The question is</u></em>
What is the volume of the open top box as a function of the side length x in cm of the square cutouts?
see the attached figure to better understand the problem
Let
x -----> the side length in cm of the square cutouts
we know that
The volume of the open top box is

we have



substitute

Find the domain for x
we know that

so
The domain is the interval (0,5)
The domain is all real numbers greater than zero and less than 5 cm
therefore
The volume of the open top box as a function of the side length x in cm of the square cutouts is

Answer:
area of trapezium:
a+b divided by 2, times by the height.
so its 8+20=28.
28/2=14.
14*14=196.
area=196
Step-by-step explanation: