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olasank [31]
2 years ago
5

Solve 2y - 5 over 3 = 4y - 1 over 2

Mathematics
1 answer:
ololo11 [35]2 years ago
4 0
\frac{2y - 5}{3} = \frac{4y - 1}{2}
3(4y - 1) = 2(2y - 5)
3(4y) - 3(1) = 2(2y) - 2(5)
12y - 3 = 4y - 10
8y - 3 = -10
8y = -7
\frac{8y}{8} = \frac{-7}{8}
y = -0.875
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For a first term of 1 and a common ratio of 2, the sum of n terms of the geometric series is given by ...

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