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olasank [31]
3 years ago
5

Solve 2y - 5 over 3 = 4y - 1 over 2

Mathematics
1 answer:
ololo11 [35]3 years ago
4 0
\frac{2y - 5}{3} = \frac{4y - 1}{2}
3(4y - 1) = 2(2y - 5)
3(4y) - 3(1) = 2(2y) - 2(5)
12y - 3 = 4y - 10
8y - 3 = -10
8y = -7
\frac{8y}{8} = \frac{-7}{8}
y = -0.875
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F(x)=4x-1<br> G(x)=x+3<br> Find f(x)+g(x)
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Answer:

Answer is 5x+2

Step-by-step explanation:

Given \: f(x) = 4x - 1 \:  \: and \:  \\ g(x) = x + 3 \\ f(x) + g(x) = 4x -1    + x + 3 \\  = 5x + 2

<em>HAVE A NICE DAY</em><em>!</em>

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choli [55]

Answer:

The set of solutions is \{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number}  \}

Step-by-step explanation:

The augmented matrix of the system is \left[\begin{array}{ccccc}3&6&6&-9\\-2&-3&-3&3\end{array}\right].

We will use rows operations for find the echelon form of the matrix.

  • In row 2 we subtract \frac{2}{3} from row 1. (R2- 2/3R1) and we obtain the matrix \left[\begin{array}{cccc}3&6&6&-9\\0&1&1&-7\end{array}\right]
  • We multiply the row 1 by \frac{1}{3}.

Now we solve for the unknown variables:

  • x_2+x_3=-7, x_2=-7-x_3
  • x_1+2x_2+2x_3=-2, x_1+2(-7-x_3)+2x_3=-2 then x_1=12

The system has a free variable, the the system has infinite solutions and the set of solutions is \{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number}  \}

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Step-by-step explanation:

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• a parallelogram with sides 40 m and 26 m (the 26-m side corresponds to the aforementioned hypotenuse)

• another triangle with two known legs of length 20 m and 26 m

Find the height of the right triangle using the Pythagorean theorem. If the height is h, then

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This height is common to all three shapes.

Now find the area of each shape.

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Then the total area of the shaded region is 1320 m².

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