The correct option is: B. 
<u><em>Explanation</em></u>
<u>The general form of growth equation</u> is:
, where A = final amount, P = initial amount, r = growth rate in decimal form and t = time duration
Here, the speed of the rocket at the beginning was 5,000 kilometers per hour and at the end will be 25,000 kilometers per hour. The speed increases at a rate of 4.3% per minute.
That means, 
Now <u>plugging these values into the above equation</u>, we will get......

So, the equation that could be used to determine the time for the speed of the rocket to reach 25,000 kilometers per hour will be: 
Answer: Y= - 1/2x - 8
If you move y to one side by itself that’s what you’ll get and you can check this answer by multiplying each side by 2 and moving the x ti the left side and you’ll get your beginning equation
If it not right feel free to comment and tell me
5a + 15 = 24b so,
10a + 30 = 48b,
sub to third equation,
10a + 30 + 35c = 49
10a + 35c = 19
perform elimination with second equation
10a + 45c = 21
10a + 35c = 19
________________-
10c = 2
c = 1/5
sub to second equation,
10a + (45)(1/5) = 21
10a + 9 = 21
10a = 12
a = 6/5
sub to first equation
(5)(6/5) - 24b = -15
6 + 15 = 24b
21 = 24b
b = 7/8
redo the calculations, correct me if I'm wrong
Given:
Pool swimming Ocean swimming Total
Age 30 and younger 228 54 282
Over 30 years old 142 185 327
total 370 239 609
Frequencies:
Pool swimming Ocean swimming Total
Age 30 and younger 228/609 = 0.37 54/609 = 0.09 282/609 = 0.46
Over 30 years old 142/609 = 0.23 185/609 = 0.30 327/609 = 0.54
<span>total 370/609 = 0.61 239/609 = 0.39 609/609 = 1.00</span>
<span>The relative frequency (rounded to the nearest hundredth) of a person over 30 years old who prefers to swim in the ocean is 0.30</span>
Answer:
√y/y c.
Step-by-step explanation:
2y/√4y^3
= 2y / 2 y^3/2
= 1 / √y
= √y/y