Around 2.232 to the nearest hundredth

Three friends each have some ribbon. Carol has 90 inches of ribbon, Tino has 7.5 feet of ribbon, and baxterhas 3.5 yards of ribb

Eddi Din [679]

Carol has 15 feet of ribbon

6 0

3 years ago

G.SRT.B.5 Worksheet #2

Yanka [14]

B): x=8, y=8root2, z=16
c): x=4, y=12, z=8root3
The ones later one you can do by your self.
30 60 90 triangle side ratio: 1:root3:2
90 45 45 triangle side ratio: 1:1:root2

4 0

2 years ago

An aquarium with a square base has no top. There is a metal frame. Glass costs 8 dollars/m^2 and the frame costs 7 dollars/m. Th

Irina-Kira [14]

Given that the volume of the aquarium is 20m^3.

Volume = Area of Base x height

Area of Base = Volume / height = 20/h

Given that the aquarium has a square base.

Area of square = l^2

Thus, the length of the base of the aquarium is $\sqrt{area \ of \ base} = \sqrt{ \frac{20}{h} }$

The frame is to cover 8 sides with the length equal to the length of the base and 4 sides with the length of the height.

Thus, the total perimeter of the frame is given by $8\sqrt{\frac{20}{h}}+4h= \sqrt{64\left(\frac{20}{h}\right)}+4h = \sqrt{\frac{1,280}{h}}+4h$

Area of the four side faces of the aquarium is 4 times the length of the base times the height = $4\times\sqrt{ \frac{20}{h} }\times h=\sqrt{16\left(\frac{20}{h}\right)h^2}=\sqrt{320h}$

Total area to be covered by grass is the base and the four side faces and is given by $\frac{20}{h}+\sqrt{320h}$

Cost of the entire metal frame = $7\left(\sqrt{\frac{1,280}{h}}+4h\right)= \sqrt{49\left(\frac{1,280}{h}\right)}+7(4h) = \sqrt{\frac{62,720}{h}}+28h$

Cost of the entire grass = $8\left(\frac{20}{h}+\sqrt{320h}\right)=\frac{160}{h}+\sqrt{64(320h)}=\frac{160}{h}+\sqrt{20,480h$

Therefore, total cost in terms of the height, h, is given by

$C=\sqrt{\frac{62,720}{h}}+28h+\frac{160}{h}+\sqrt{20,480h$

3 0

4 years ago

Using what you know about right triangle trigonometry, salt the triangle round the side to the nearest 10th and angle measures t

Elden [556K]

Answer:

Angle A = 49° Angle B = 41° Side AB = 30.5

Step-by-step explanation:

Let's work out Angle A and Angle B first. We are given AC and CB, therefore AB must be the hypotenuse as it is the longest side.

AC and CB must be the opposite and adjacent sides, therefore we can use tan(x) = Opposite/Adjacent for working out both Angle A and Angle B.

Angle A:

tan(A) = 23/20 For Angle A, CB (23) is the side opposite the angle and AC (20) is the side in between Angle A and the right angle, also the adjacent side.

A = $tan^{-1}(\frac{23}{20})$ We do the inverse of tan here.

A = 48.9909131

A = 49° Rounding to the nearest degree simply means to the nearest whole number.

Angle B:

tan(B) = 20/23 For Angle B, AC (20) is the side opposite the angle and CB (23) is the side in between Angle B and the right angle, also the adjacent side.

B = $tan^{-1}(\frac{20}{23})$

B = 41.0090869

B = 41°

Side AB:

We can just use Pythagoras' Theorem here to work out AB, but I will also use trigonometry to show you how you can use both formulas. When I use trigonometry, I will only be using Angle A as an example.

Pythagoras' Theorem: $a^{2} + b^{2} = c^{2}$

AC = 20 = a

CB = 23 = b

$20^{2} + 23^{2} = c^{2}$

929 = $c^{2}$

c = $\sqrt{929}$

c = 30.47950131

c = 30.5 Rounding to the nearest 10th simply means rounding to 1 decimal place.

Trigonometry: SOHCAHTOA

Angle A = 49°

AC = 20 I will use AC as our adjacent side instead of CB. They will both give us the same answer anyways.

AB will always be the hypotenuse in the given right-angled triangle.

cos(x) = Adjacent/Hypotenuse

cos(49) = 20/AB

ABcos(49) = 20 Here we multiply by AB, our hypotenuse.

AB = 20/cos(49) Now we divide by cos(49)

AB = 30.48506173 As you can see here, this answer is different from the Pythagoras' Theorem one because we rounded our angle values, meaning out angle values aren't exact! Instead, use Pythagoras' Theorem here for more accurate results instead of Trigonometry.

AB = 30.5 They still give us the same answer in the end!

I hope this helps you!! ^-^

7 0

3 years ago

A cat is watching a bird in a tree nearby the tree is approximately 20 feet from the cat ground distance if the cats line of sig

Elina [12.6K]

Answer:

X=20Tan(25)

Step-by-step explanation:

So because the cat is looking at the tree it is a strait line making a right triangle with the tree. The cat spots the bird 25 degrees up in the tree making a triangle. Then use SohCahToa, and because u have the adjacent side use Tangent because you are missing the opposite side of the angle. There are a few other ways to find it but that is the simplest way to perform this, GOOD LUCK!

3 0

3 years ago