Question

Given the graph, find an equation for the parabola.

Answer 1

Answer:

$\Large \boxed{\sf \bf \ \ y=\dfrac{1}{16}(a-3)^2-2 \ \ }$

Step-by-step explanation:

Hello, please consider the following.

When the parabola equation is like

$y=a(x-h)^2+k$

The vertex is the point (h,k) and the focus is the point (h, k+1/(4a))

As the vertex is (3,-2) we can say that h = 3 and k = -2.

We need to find a.

The focus  is (3,2) so we can say.

$2=-2+\dfrac{1}{4a}\\\\\text{*** We add 2. ***}\\\\\dfrac{1}{4a}=2+2=4\\\\\text{*** We multiply by 4a. ***}\\\\16a=1\\\\\text{*** We divide by 16. ***}\\\\a=\dfrac{1}{16}$

So an equation for the parabola is.

$\large \boxed{\sf y=\dfrac{1}{16}(a-3)^2-2 }$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you