Question

The perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and W is the width of the rectangle. Can the perimeter of the rectangle be 60 units when its width is 12 units and its length is 18 units?
A)No. If the rectangle has L = 18 and W = 12, P would not equal 60.
B) No. The rectangle cannot have P = 60 and L = 18 because L + W is less than 24.
C) Yes. The rectangle can have P = 60 and L = 18 because 60 = 24 + 18.
D)Yes. The rectangle can have P = 60 and L = 18 because P = 2(18) + 2(12) would equal 60.

Answer 1

Answer:

D)Yes. The rectangle can have P = 60 and L = 18 because P = 2(18) + 2(12) would equal 60

Step-by-step explanation:

The formula for the perimeter of a rectangle is $P=2L+2W$.

If the width is $W=12\:units$ and the length is $L=18\:units$, then the perimeter becomes:

 $P=2\times 12+2\times 18$.

 $\implies P=24+36$.

 $\implies P=60$.

Therefore the answer is

D)Yes. The rectangle can have P = 60 and L = 18 because P = 2(18) + 2(12) would equal 60

Answer 2

Answer:

D)Yes. The rectangle can have P = 60 and L = 18 because P = 2(18) + 2(12) would equal 60

Step-by-step explanation:

The formula for the perimeter of a rectangle is .

If the width is  and the length is , then the perimeter becomes:

 .

 .

 .

Therefore the answer is

D)Yes. The rectangle can have P = 60 and L = 18 because P = 2(18) + 2(12) would equal 60