Answer:
see below
Step-by-step explanation:
The problem statement seems to presume you have seen an exponential function like this written as ...
f(t) = a0·(1 +r)^t
where a0 is the value corresponding to f(0) and "r" is the fractional rate at which the value increases for each increment of t.
Here, 1+r corresponds to 1.04 in the given function, so r = 0.04 = 4%. When the value is <em>greater than 0</em>, it means there is an <em>increase</em> by that fraction each time t increases by 1.
Here, t is not defined, either, but it would usually be used to represent years in a situation like this. (In other situations, it might represent months, hours, or millenia.)
Hence, the appropriate choice is the one that describes a 4% annual increase.
Answer:
g00glek saphari
Step-by-step explanation:
youneedtouseg00glek
D is halfway between A and B
so the coordinates of D are (2,2)
E is halfway between A and C so the coordinates of E are (-1,1)
now you need to find the gradient/slope of DE and BC using the formula:
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>D</u><u>E</u><u>:</u><u> </u></h3>
SUB IN COORDINATES OF D AND E
therefore the gradient of DE is 1/3.
<h3>
<u>G</u><u>r</u><u>a</u><u>d</u><u>i</u><u>e</u><u>n</u><u>t</u><u> </u><u>o</u><u>f</u><u> </u><u>B</u><u>C</u><u>:</u></h3>
<em>S</em><em>U</em><em>B</em><em> </em><em>I</em><em>N</em><em> </em><em>C</em><em>O</em><em>O</em><em>R</em><em>D</em><em>I</em><em>N</em><em>A</em><em>T</em><em>E</em><em>S</em><em> </em><em>O</em><em>F</em><em> </em><em>B</em><em> </em><em>A</em><em>N</em><em>D</em><em> </em><em>C</em>
<em>
</em>
therefore the gradient of BC is -2/-6 which simplifies to 1/3.
<h3>
therefore, BC and DE are parallel as they both have a gradient/slope of 1/3 and parallel lines have the same gradient</h3>
Yes as long as one side on a square is the same on another they are the copies of each other
I don’t know if this is what you’re asking but 14.1-191 = -176.9
