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goldenfox [79]
3 years ago
14

6/8 time is twice as fast as 3/4 True or False

Mathematics
2 answers:
vovangra [49]3 years ago
4 0

Answer:

true

Step-by-step explanation:

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madam [21]3 years ago
4 0

Answer:

False

Step-by-step explanation:

Multiplying the numerator and the denominator by a number is basically multiplying the equation by 1, meaning that it won't change the value.

Keeping that in mind, 6/8 can be reduced to 3/4 by multiplying the top and bottom by 1/2, meaning they are equal.

To actually multiply a fraction to make it 2 times itself, you only multiply the numerator(top), not the denominator(bottom).

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(t-4)(3t+1)(t+2)=0 hats the answer
trasher [3.6K]
(3t² +t -12t - 4)(t+2)=0
(3t³ - 5t² -26t -8) =0
t = -2
7 0
3 years ago
Read 2 more answers
Find the equivalent expression by drawing a line from the left column to the right
Gala2k [10]

Answer/Step-by-step explanation:

2(3x - 1) = 2*3x 2*-1 = 6x - 2

(x*y)2 = (xy)2 = 2xy

2(2x - 3) = 2*2x 2*-3 = 4x - 6

3x + 4x + 2 = (3x + 4x) + 2 = 7x + 2

7x - 7 = 7(x) - 7(1) = 7(x - 1)

x(6 + 9) = x(15) = 15x

2 + 9x + 1 + 3x = (9x + 3x) + (2 + 1) = 12x + 3

4(x + 2) + x = 4x + 8 + x = 4x + x + 8 = 5x + 8

6 0
3 years ago
The thickness of a plastic film (in mils) on a substrate material is thought to be influenced by the temperature at which the co
statuscvo [17]

Answer:

Step-by-step explanation:

Hello!

The objective is to test if rising the process temperature reduces the thickness of the plastic film that coats a substrate material To do so, two samples of substrates are coated at different temperatures:

Sample 1

X₁: Thickness of the plastic film after the substrate is coated at 125F

n₁=11

X[bar]₁= 101.28

S₁= 5.08

Sample 2

X₂: Thickness of the plastic film after the substrate is coated at 150F

n₂= 13

X[bar]₂= 101.70

S₂= 20.15

Does the data support this claim? Use the P-value approach and assume that the two population standard deviations are not equal.

Now if the higher the heat, the thinner the thickness of the plastic coating, then the average thickness of the coating done at 150F should be less than the average thickness of the coating done at 125F, symbolically: μ₂ < μ₁

Then the hypotheses are:

H₀: μ₂ ≥ μ₁

H₁: μ₂ < μ₁

α:0.05 (there is no α level stated so I've chosen the most common one)

Assuming that both variables have a normal distribution since the population standard deviations are not equal, the statistic to use is the Welch's t-test:

t= \frac{(X[bar]_2-X[bar]_1)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } } ~~t_w

t_{H_0}= \frac{(101.7-101.28)-0}{\sqrt{\frac{(20.15)^2}{13} +\frac{(5.08)^2}{11} } } = 0.072

This test is one-tailed to the left, meaning that you'll reject the null hypothesis at small values of t. The p-value is also one-tailed and has the same direction as the test. To calculate it you have to first calculate the degrees of freedom of the Welch's t:

Df_w= \frac{(\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} )^2}{\frac{(\frac{S^2_1}{n_1})^2 }{n_1-1}+\frac{(\frac{S^2_2}{n_2} )^2}{n_2-1}  }

Df_w= \frac{(\frac{5.08^2}{11} +\frac{20.15^2}{13} )^2}{\frac{(\frac{5.08^2}{11})^2 }{10} +\frac{(\frac{20.15^2}{13} )^2}{12} } = 13.78

The distribution is a Student's t with 13 degrees of freedom, then you can calculate the p-value as:

P(t₁₃≤0.072)= 0.4718

Using the p-value approach, the decision rule is:

If the p-value ≤ α, the decision is to reject the null hypothesis.

If the p-value > α, the decision is to not reject the null hypothesis.

The p-value is greater than the significance level, so the decision is to nor reject the null hypothesis.

Using a significance level of 5%, there is no significant evidence to support the claim that the average thickness pf the plastic coat processed at 150F is less than the average thickness pf the plastic coat processed at 125F.

I hope you have a SUPER day!

4 0
3 years ago
Michele wanted to measure the height of her school’s flagpole. She placed a mirror on the ground 48 feet from the flagpole, then
yulyashka [42]
Height of the flagpole = x
distance from flagpole to the mirror = 48 ft
height of Michele = 5 ft
distance from Michele to the mirror = 12 ft

Now, set the proportion.

x/48 = 5/12
48 * x/48 = 5/12 * 48
x = 240/12
x = 20

So, the height of the flagpole is 20 ft.

HOPE THIS HELPS!!!!
5 0
3 years ago
Express the measurement 4.29478416 kg with 8, 6, 4, and 2 significant figures
ira [324]

Significant figures refers to digits within a number which must be included in other depict correct quantity of the figure.

  • 4.29478416 = 4.2947842 ( 8 significant figures)
  • 4.29478416 = 4.29478 (6 significant figures)
  • 4.29478416 = 4.295 ( 4 significant figures)
  • 4.29478416 = 4.3 (2 significant figures)

To round a number to a certain number of significant figures,

  • Only leading 0 which comes before the decimal Point are regarded as insignificant.
  • Once the number of significant figures have been identified, the next number after this is either rounded up to 1 and added to the last value(if number is ≥5) or rounded to 0 (if number is less than 5)

Learn. More : brainly.com/question/13386983?referrer=searchResults

3 0
3 years ago
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