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goldenfox [79]
3 years ago
14

6/8 time is twice as fast as 3/4 True or False

Mathematics
2 answers:
vovangra [49]3 years ago
4 0

Answer:

true

Step-by-step explanation:

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madam [21]3 years ago
4 0

Answer:

False

Step-by-step explanation:

Multiplying the numerator and the denominator by a number is basically multiplying the equation by 1, meaning that it won't change the value.

Keeping that in mind, 6/8 can be reduced to 3/4 by multiplying the top and bottom by 1/2, meaning they are equal.

To actually multiply a fraction to make it 2 times itself, you only multiply the numerator(top), not the denominator(bottom).

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Find the length of the third side. If necessary, round to the nearest tenth. 10 14 ​
abruzzese [7]

Answer:

9.8 units

Explanation:

According to Pythagoras theorem, the square of length of the hypotenuse is equal to the sum of squares of lengths of other two sides.

Let the third side be x units.

Then,

x² + 10² = 14²

=> x² + 100 = 196

=> x² = 196 - 100

=> x² = 96

=> x = √96

=> x = 4√6

=> x = 9.79....

=> x = 9.8 (Rounding to the nearest tenths)

So, the length of the third side is 9.8 units.

5 0
3 years ago
Crisps <br> normal price £1.43 <br> three for the price of two<br> what is the total of 6 packets
Anettt [7]

Answer:

3 packs equal the price of two, therefore 1.43•2= 2.86

and 6 packs equal the price of 4, so 2.86•2= 5.72

7 0
3 years ago
I need to know the area of this triangle and I would like to have an explanation because I dont know how to do it I know the for
Anna [14]

Answer: 69

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Piano lessons cost $15. What expressions could be used to find the cost in dollars of 5 lessons
kirill115 [55]
Just write 15x5. Hope I helped
5 0
3 years ago
Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000
zvonat [6]

Answer:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

A = \int\limits^t_ {1} \,{13\cdot x^{3}}  dx

A = 13 \int\limits^t_1 {x^{3}} \, dx

A = \frac{13}{4}\cdot (t^{4}-1)

Evaluated areas are presented below:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

8 0
4 years ago
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