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3 years ago

1. How many solutions are there for the equation? x2 + 16 = 8x (Points : 1)

2 answers:

4 0

$x^2 + 16 = 8x\\\\x^2-8x+16=0\\\\x^2-4x-4x+16=0\\\\x(x-4)-4(x-4)=0\\\\(x-4)(x-4)=0\\\\(x-4)^2=0\ \ \ \Leftrightarrow\ \ \ x-4=0\ \ \ \Leftrightarrow\ \ \ x=4\\\\ Ans.\ One\ solution$

defon3 years ago

3 0

Every equation that has an ' x² ' in it has two solutions.

If it's a perfect square, then the solutions are equal, and they look like only 1.

Both solutions to this equation are [ x = 4 ] .

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What’s the mean of all odd integers between 16 and 47

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3 years ago

Please answer the question in the photo, thanks!

belka [17]

Answer:

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right )$

We rearrange the fractions as improper fractions for easier division as follows;

$2\dfrac{1}{3} = \dfrac{7}{3}$

$-3\dfrac{2}{3} = -\dfrac{11}{3}$

Therefore, we have;

$2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}$

$\therefore 2\dfrac{1}{3} \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}$

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3 years ago