Answer:
( x - 2 )^2 + ( y - 1 )^2 = 1
Step-by-step explanation:
As i previously explained,
The general form of equation for a circle is ( x - h )^2 + ( y - k )^2 = r^2.
h and k are the co-ordinates of the center of circle and r is the radius
Here, We have (2,1) as the co-ordinates of the center of circle
Now,
( x - h )^2 + ( y - k )^2 = r^2
or,( x - 2 )^2 + ( y - 1 )^2 = r^2
The radius of the circle is 1 units(from figure)
So, put that in, we get
( x - 2 )^2 + ( y - 1 )^2 = 1^2
or, ( x - 2 )^2 + ( y - 1 )^2 = 1
You can simplify this or leave it here.
Add the numbers 7 + 10
17 - 7j = -10 - 4j
subtract 17 from both sides
-7j = -27 - 4j
add 4j to both sides
-3j = -27
divide both sides by -3
j = 9
I think it will be w+15 because if you write 15w that means 15×w and the others don't make sense..
![\left[\begin{array}{cc}1&1\\2&-3\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\3\end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%261%5C%5C2%26-3%5Cend%7Barray%7D%5Cright%5D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%5C%5Cy%5Cend%7Barray%7D%5Cright%5D%20%3D%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D4%5C%5C3%5Cend%7Barray%7D%5Cright%5D%20)