Solve for the two unknown angles in the following isosceles triangle and please show all work!

Mathematics

1 answer:

kramer3 years ago

3 0

Answer: 65°

Step-by-step explanation: In the photo

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Which of the sequences is an arithmetic sequence?

Bogdan [553]

<h3>Answer: Choice A</h3>

This is because we're adding -6 to each term, i.e. subtracting 6 from each term, to get the next term

-2+(-6) = -8
-8+(-6) = -14
-14+(-6) = -20
-20+(-6) = -26

and so on. The gap between adjacent terms is the same width. We say that the common difference is d = -6.

5 0

3 years ago

assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the

drek231 [11]

Answer:

65.3658 inches

Step-by-step explanation:

Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value $x_{0}$ such that $P(X < x_{0}) = 0.76$ , but, $0.76 = P(X < x_{0}) = P((X-63.6)/2.5 < (x_{0}-63.6)/2.5) = P(Z < (x_{0}-63.6)/2.5)$ , i.e., $(x_{0}-63.6)/2.5$ is the 76th percentile of the standard normal distribution. So, $(x_{0}-63.6)/2.5 = 0.7063$ , $x_{0} =63.6+(2.5)(0.7063) = 65.3658$ . Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.