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3 years ago

What 8s the answer please I need help

Mathematics

2 answers:

balu736 [363]3 years ago

5 0

10 × 2 tens = 10 × 20
10 × 20 = 200
200 = 20 tens

Sphinxa [80]3 years ago

4 0

Tha answer
s are 200 and there are 20 tens

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I'll assume the ODE is

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Solve the homogeneous ODE,

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Substituting this into (1) gives

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For the nonhomogeneous ODE (2),

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take the ansatz

$y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}$

Substitute (2) into the ODE to get

$b(4x+4) e^{2x} - 3b(2x+1)e^{2x} + 2bxe^{2x} = e^{2x} \implies b=1$

Lastly, for the nonhomogeneous ODE (3)

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take the ansatz

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Then the general solution to the ODE is

$\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}$

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