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ANEK [815]
3 years ago
12

Where do the slope and y-intercept show up in the tables and graphs?

Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0
Positive side of graph?
natima [27]3 years ago
4 0

Answer:

Solution: The general form of the line on a graph is y = mx+c,

where y is the coordinate of the point along the y-axis,

x is the coordinate of the point along the x-axis,

m is the slope of the line or arc tan of the angle the line makes with the x-axis, and

c is the intercept the line makes on the y-axis.

Suppose we want a line having a slope of 45º with the x-axis and passes through point P (4,6), the equation of the line is

y = mx + c

6 = tan 45 * 4 + c, or

6 = 4 + c, or

c = 6–4 = 2.

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bazaltina [42]

Answer:

C

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Use the graph of f '(x) below to find the x values of the relative maximum on the graph of f(x):
Lana71 [14]

Answer:

You have relative maximum at x=1.

Step-by-step explanation:

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f' greater than 0 means that f is increasing there.

f' is less than 0 when the curve is below the x-axis.

f' is less than 0 means that f is decreasing there.

Since we are looking for relative maximum(s), we are looking for when the graph of f switches from increasing to decreasing. That forms something that looks like this '∩' sort of.

This means we are looking for when f' switches from positive to negative. At that switch point is where we have the relative maximum occurring at.

Looking at the graph the switch points are at x=0, x=1, and x=2.

At x=0, we have f' is less than 0 before x=0 and that f' is greater than 0 after x=0.  That means f is decreasing to increasing here. There would be a relative minimum at x=0.

At x=1, we have f' is greater than 0 before x=1 and that f' is less than 0 after x=1. That means f is increasing to decreasing here. There would be a relative maximum at x=1.

At x=2, we have f' is less than 0 before x=2 and that f' is greater than 0 after x=2. That means f is decreasing to increasing here. There would be a relative minimum at x=2.

Conclusion:

* Relative minimums at x=0 and x=2

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