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Point sloe is
y-y1=m(x-x1)
slope=m
a ponint is (x1,y1)
slope=(y2-y1)/(x2-x1)
(x,y)
(5,-3)
(-2,9)
slope=(9-(-3))/(-2-5)=12/-7=-12/7
m=-12/7
a point is (5,-3)
x1=5
y=-3
y-(-3)=-12/7(x-5)
y+3=-12/7(x-5)
2nd one
Answer:
x = 9
y = 9√3 = 15.6
Step-by-step explanation:
The triangle given is a right triangle, therefore:
✔️apply trigonometric ratio formula to find x:
Reference angle = 60°
Hypotenuse = 18
Adjacent = x
Thus:
Cos (60) = x/18
Multiply both sides by 18
18×cos(60) = x
9 = x
x = 9
✔️find y by applying pythagorean theorem:
y² = 18² - x² (pythagorean theorem)
y² = 18² - 9² (substitution)
y² = 243
y = √243
y = √(81*3)
y = 9√3 = 15.6
-2+-2+-2+-2
-4+-4
=-8
hope this helps:)
It is asking for the tangent ratio at B.
In my answer; angle=theta
tan(theta)=opposite/adjacent
tan(theta)= 3/2
