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alexgriva [62]
3 years ago
5

16 24 36 54 COMMON RATIO

Mathematics
1 answer:
Yakvenalex [24]3 years ago
4 0

All of them can be divided by 2 so ratio 1:2 is a common ratio

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Write the following ratios in simplest form.<br><br>35:100​
Andru [333]

Answer:

7:20

Step-by-step explanation:

divide both by 5 to simplify

3 0
3 years ago
According to the graph, if only one unit was produced, the cost per unit would be $1.00. In
riadik2000 [5.3K]

Answer:

Modify (restrict) the function's Domain as indicated below

Step-by-step explanation:

The factory would study the expenses involved with setting the factory into production, wages for workers' salaries, and other factory running expenses into the total cost of producing the units (such would obviously drastically change the graph from the one presented), and make sure that there is a threshold at least on the "breaking even" with the estimated revenue coming from the units produced/ordered.

That threshold can be set to a "<em>minimal</em>" number of units ordered in order to start production. If one wants to use the original graph, with some minor modifications, one can change it so it starts from that threshold point onward. For example, if the minimal number of units to be produced in order to "break even" considering the "revenue minus total expenses larger than zero" condition, the given graph could be modified to the one shown in red in the image attached. In such graph we are estimating that the positive "revenue minus total cost" break even point is at the production of 13,000 units, so we set the starting of the piece-wise function there, and use a non-solid dot to indicate that the number of units produce should be strictly larger than the break-even point (13,000 units) in order to be profitable. This involves a change in the original function's Domain, restricting its first section from the original one (which starts at zero: 0\leq x\leq 25,000) to a domain that starts at a number of units strictly larger than 13,000 (13,000) in our example

3 0
4 years ago
A group of students is collecting books to add to their librarby. The table shows the number of books in the librarby after 1, 3
Grace [21]

Answer:

(7,48)

Step-by-step explanation

the books go up by ten  and the days go up by 2

6 0
3 years ago
Read 2 more answers
|y+4|&lt;1 Solve and Show your work?
kobusy [5.1K]

\sqrt{815}
6 0
3 years ago
I don’t know how to solve this
Lady_Fox [76]

Answer:

\theta =2\pi k,\ \ k\in Z\ \\\text{or}\ \\\theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z

Step-by-step explanation:

Given:

\cos \theta-\sqrt{3}\sin \theta=1

Divide this equation by 2:

\dfrac{1}{2}\cos \theta-\dfrac{\sqrt{3}}{2}\sin \theta=\dfrac{1}{2}

Note that

\cos \dfrac{\pi }{3}=\dfrac{1}{2}\\ \\\sin \dfrac{\pi }{3}=\dfrac{\sqrt{3}}{2}

So, the previous equation is

\cos \dfrac{\pi}{3}\cdot \cos \theta-\sin \dfrac{\pi}{3}\cdot \sin \theta=\dfrac{1}{2}

Remind that

\cos x\cos y-\sin x\sin y=\cos (x+y),

then

\cos \left(\dfrac{\pi}{3}+\theta\right)=\dfrac{1}{2}

The solution of this equation is

\dfrac{\pi}{3}+\theta=\pm \arccos \dfrac{1}{2}+2\pi k,\ \ k\in Z\\ \\\dfrac{\pi}{3}+\theta=\pm \dfrac{\pi}{3}+2\pi k,\ \ k\in Z\\ \\\theta =2\pi k,\ \ k\in Z\ \text{or}\ \theta=-\dfrac{2\pi}{3}+2\pi k,\ \ k\in Z

8 0
3 years ago
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