Find the slope between (3,2) and (-2,3)

1 answer:

3 0

$(x_1;\ y_1);\ (x_2;\ y_2)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\\\\(3;\ 2);\ (-2;\ 3)\\\\\boxed{m=\dfrac{3-2}{-2-3}=\dfrac{1}{-5}=-\dfrac{1}{5}}$

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