Three ordered pairs would be
x y
0, -15
1, -12
2, -9
ect...
Alright, lets get started.
The given function is :
When we find the domain of any function, we consider the domian is set of input values for which function should remain real and defined.
In this given function , we have not given any points where function seems going undefined.
Hence the domain is : (-∞, +∞) : Answer
Hope it will help :)
Answer: (a). 99 percent of the sample proportions results in a 99% confidence interval that includes the population proportion.
(b). 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.
Step-by-step explanation:
(a). 99 percent of the sample proportions results in a 99% confidence interval that includes the population proportion.
Explanation: If multiple samples were drawn from the same population and a 99% CI calculated for each sample, we would expect the population proportion to be found within 99% of these confidence intervals.
(b). 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.
Explanation: The 99% of the confidence intervals includes the population proportion value, it means, the remaining (100% – 99%) 1% of the intervals does not includes the population proportion.
If multiple samples were drawn from the same population and a 99% CI calculated for each sample, we would expect the population proportion to be found within 99% of these confidence intervals and 1 percent of the sample proportions results in a 99% confidence interval that does not include the population proportion.
Answer:
3x>12 2x/3 ≤ 6
3x>12, x = 4 2x/3, x = 2 ≤ 6
<h3>Answer:</h3>
2.25
<h3>Explanation:</h3>
Consider the square ...
... (x+a)² = x² +2ax +a²
The constant term (a²) is the square of half the x-coefficient: a² = (2a/2)².
The x-coefficient in your expression is 3. The square of half that is ...
... (3/2)² = 9/4 = 2.25
Adding 2.25 to both sides gives ...
... x² +3x + 2.25 = 6 + 2.25
... (x +1.5)² = 8.25 . . . . completed square
