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sammy [17]
2 years ago
9

Which of the follow triangles is similar to APOR?

Mathematics
1 answer:
Paul [167]2 years ago
7 0

Answer:

D

Step-by-step explanation:

For each triangle, you are given two sides and the included angle (the one between those 2 sides). That's side-angle-side, so it is S-A-S.

The SAS Rule for Similar Triangles says that for 2 triangles X and Y, if you have the SAS of one and the SAS of the other, then X and Y are similar (same shape and proportions) if

(a) the angle in X is congruent (same) as the angle in Y

(b) the ratio between the two given sides in X is the same as the ratio between the two given sides in Y

For this particular problem, the ratio PR/PQ = 18/21 = 6/7 if you simplify by dividing both top and bottom by 3.

So we are looking for another triangle where we have the same ratio. (Put the smaller number on top, in the fraction.)

Answer A:  12/15 simplifies to 4/5, wrong answer

Answer B:  9/12 simplifies to 3/4, wrong answer

Answer C:  6/10 simplifies to 3/5, wrong answer

Answer D: 15/17.5 looks harder, because there is a decimal in it. But we know 17.5 is just 17 and a half, so I would first multiply top and bottom by 2

We get 30/35. That looks a lot better. Now it is easier to see we can divide both top and bottom by 5.

We get 6/7! That is the correct answer, so D is the triangle similar to PQR.

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y=-4x+48
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3 years ago
3 gallons But in pints
MakcuM [25]

Answer: 24 pints

Step-by-step explanation:

multiply the volume value by 8

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8 0
3 years ago
Simplify the expression (8n^4-6n+8n^2)+(6n^4-3n+7)
Marysya12 [62]

Answer:

=14n⁴+8n²-9n+7

Step-by-step explanation:

(8n⁴-6n+8n²)+(6n⁴-3n+7)

=8n⁴-6n+8n²+6n⁴-3n+7

=8n⁴+6n⁴+8n²-6n-3n+7

=14n⁴+8n²-9n+7

8 0
2 years ago
In a store, a sample of 60 pens was selected from a box of 1,200 pens. Of these 60, 4 pens did not work. About how many pens cou
Lapatulllka [165]
Ok so if 1200 total pens and 60 were taken that's a ratio of 1200/60=20

out of 60pens 4 didn't work, again ratio is 4/60=1/15 so about 1/15 of the pens didn't work. 

so we have 1200pens * 1/15broken ratio = 80 pens or we can say 

20*4=80pens won't work from 20 groups of 60 and 4 out of 60 not working is 20*4=80 not working from total batch of 1200.

hope this helps you some! thank you!!!!!!!!!
3 0
3 years ago
manufacturing company produces digital cameras and claim that their products maybe 3% defective. A video company, when purchasin
alexdok [17]

Answer:

P(X>17) = 0.979

Step-by-step explanation:

Probability that a camera is defective, p = 3% = 3/100 = 0.03

20 cameras were randomly selected.i.e sample size, n = 20

Probability that a camera is working, q = 1 - p = 1 - 0.03 = 0.97

Probability that more than 17 cameras are working P ( X > 17)

This is a binomial distribution P(X = r) nCr q^{r} p^{n-r}

nCr = \frac{n!}{(n-r)!r!}

P(X>17) = P(X=18) + P(X=19) + P(X=20)

P(X=18) = 20C18 * 0.97^{18} * 0.03^{20-18}

P(X=18) = 20C18 * 0.97^{18} * 0.03^{2}

P(X=18) = 0.0988

P(X=19) = 20C19 * 0.97^{19} * 0.03^{20-19}

P(X=19) = 20C19 * 0.97^{19} * 0.03^{1}

P(X=19) = 0.3364

P(X=20) = 20C20 * 0.97^{20} * 0.03^{20-20}

P(X=20) = 20C20 * 0.97^{20} * 0.03^{0}

P(X=20) = 0.5438

P(X>17) = 0.0988 + 0.3364 + 0.5438

P(X>17) = 0.979

The probability that there are more than 17 working cameras should be 0.979 for the company to accept the whole batch

6 0
3 years ago
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