Answer:
I'm pretty sure it's luster!
Stress can cause a virus to switch from the lysogenic cycle to the lytic cycle.
Answer:
Many distance runners “carb load” the day before a big race. How does this eating strategy provide an advantage to the runner?
The carbohydrates cause the release of insulin.
The excess carbohydrates are converted to fats, which have a higher calorie density.
The glucose from the carbohydrates lets the muscles make excess ATP overnight.
The excess carbohydrates can be stored in the muscles as glycogen.
Explanation:
<em>During the exercise</em>, the energy is consumed in the form of glycogen that the liver provides, <em>there are evidences that maintain that the consumption of carbohydrates during prolonged sports improves fatigue resistance.
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<em>During exercise</em>, carbohydrates stored as muscle glycogen are used as a specific energy source for muscle. In the liver, however, glycogen is converted by glycogenolysis into glucose, which passes into the blood and from it to the working muscles.
<u><em>The answer is</em></u>: <u>Excess carbohydrates can be stored in the muscles as glycogen.</u>
Answer:
Map distance = Genetic distance, GD = 3.9 MU ≅ 4 MU
Explanation:
The more separated two genes are, the more chances of recombination there will be. The closer they are, the fewer chances of recombination there will be. Two genes that are very close will have a few recombination events and are strongly bounded.
To analyze the recombination frequency, we have to know that:
- 1% of recombination = 1 map unit = 1centi Morgan = 1,000,000 base pairs.
- And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products one of them results in a recombinant one.
Knowing that the genes are linked, we can calculate genetic distances between them. First, we need to identify the genotypes of the parental gametes with the ones of the recombinants. We can recognize the parental gametes in the descendants because their phenotypes are the most frequent, while the recombinants are the less frequent. So:
Parentals:
- black, curved 337
- yellow, straight 364
Recombinants:
- Black, straight 17
- yellow, curved 12
To calculate the recombination frequency we will make use of the next formula: P = Recombinant number / Total of individuals.
P = Recombinant number / Total of individuals.
P = 17 + 12 / 337 + 364 + 17 + 12
P = 29 / 730
P = 0.039
The genetic distance (GD) will result from multiplying that recombination frequency (P) by 100 and expressing it in map units (MU).
GD = P x 100
GD = 0.039 x 100
GD = 3.9 MU ≅ 4 MU
1 AU is 149597871 kilometers.
We solve
This gives us .3897114284... AU away from the sun.
