Answer:
The activation energy is 164.02 kJ/mol
Explanation:
Log (k2/k1) = Ea/2.303R × [1/T1 - 1/T2]
k1 = 8.9×10^-4 s^-1
k2 = 9.83×10^-3 s^-1
R = 8.314 J/mol.K
T1 = 540 K
T2 = 578 K
Log (9.83×10^-3/8.9×10^-4) = Ea/2.303×8.314 × [1/540 - 1/578]
1.043 = 6.359×10^-6Ea
Ea = 1.043/6.359×10^-6 = 164020 J/mol = 164020/1000 = 164.02 kJ/mol
Explanation:
To solve this problem, we need to understand the concept of precision and accuracy.
Through this understanding we apply to solve this problem.
- Precision is the ability to reproduce the same set of values in an experiment.
- Accuracy is the nearness or closeness of the measured value to the true value.
For example; if the true value is 28.0mm and the following readings were made:
A = 24.0mm, 24.0mm, 24.3mm, 23.9mm This is a precise measurement but not accurate.
B = 27.9mm, 28.0mm, 28.1mm: This is an accurate measurement because it is close to the true value.
Matter is made of what molecules and atoms are made of
<span>Helium has two valence electrons.</span>
To balance a chemical reaction, we need to remember that the number of each atom in the reactant and the product side of the equation should be equal. So, from the reaction <span>P4(s) + Cl2(g) = PCl3(l), there are 4 P atoms in the reactant, the P atoms in the prodcut side should be 4 as well. We balance as follows:
</span> P4(s) + 6Cl2(g) = 4PCl3(l)
<span>
Therefore, the coefficient of the PCl3 should be 4.
</span>
