Answer:
False
Explanation:
2CH₄ + 2O₂ ⟶ 2CO₂ + 2H₂O
Let’s count the atoms on each side of the reaction arrow.
<u>Atom</u> <u>On the left</u> <u>On the right</u>
C 2 2
H 8 4
O 4 6
C is balanced, but there are different numbers of H and O on each side.
The equation is not balanced
.
Answer:
The empirical formula is same as the molecular formula = C6H10S2O
Explanation:
we start by dividing the percentage of each of the elements by their atomic mass
Carbon = 44.4/12 = 3.7
Hydrogen = 6.21/1 = 6.21
Sulphur = 39.5/32 = 1.234375
oxygen = 9.89/16 = 0.618125
That of oxygen is smallest so we divide all by that of oxygen
C = 3.7 / 0.618125 = 6
H = 6.21/ 0.618125 = 10
S = 1.234375/ 0.618125 = 2
Automatically, oxygen is 1
So the empirical formula is;
C6H10S2O
Let’s get its molecular formula. We multiply each of the subscript by the number;
(72 + 10 + 64 + 16)n= 162
162n = 162
n = 1
So the molecular formula is same as the empirical formula
I need a picture in order to answer that question.
Answer:
28g
Explanation:
Given parameters:
Number of moles of hydrogen = 3moles
Unknown:
Mass of nitrogen used = ?
Solution:
To solve this problem, let us establish the balanced reaction equation first;
N₂ + 3H₂ → 2NH₃
From the balanced reaction equation;
3 mole of H₂ will combine with 1 mole of N₂
Now,
Mass of Nitrogen = number of moles x molar mass
Molar mass of N₂ = 2(14) = 28g/mol
Mass of Nitrogen = 1 mole x 28g/mole = 28g
