Answer:
the answer is about 62
Step-by-step explanation:
Let
represent the depth of the miner and equipments elevator, respectively. We know that equipment elevator descends with a velocity of
feet per second, and the miners one descends with a velocity of
feet per second.
If we start counting time (
) when the equipment elevator begins to descend, after
seconds its depth will be
![d_e(t) = v_et = 4t](https://tex.z-dn.net/?f=%20d_e%28t%29%20%3D%20v_et%20%3D%204t%20)
On the other hand, the miner elevator follows the same rule, but we have to use its velocity, and remember that it starts with a delay of thirty seconds:
![d_m(t) = v_m(t-30) = 15(t - 30)](https://tex.z-dn.net/?f=%20d_m%28t%29%20%3D%20v_m%28t-30%29%20%3D%2015%28t%20-%2030%29%20)
Now, we have to wait the 30 seconds of delay, and then another 14 seconds. This means that we want to know the positions of both elevators when
. Let's plug this value into the two equations:
![d_e(44) = 4\cdot 44 = 176](https://tex.z-dn.net/?f=%20d_e%2844%29%20%3D%204%5Ccdot%2044%20%3D%20176%20)
![d_m(44) = 15(44-30) = 15\cdot 14 = 210](https://tex.z-dn.net/?f=%20d_m%2844%29%20%3D%2015%2844-30%29%20%3D%2015%5Ccdot%2014%20%3D%20210%20)
So, the equipment elevator is 176 feet deep, and the miner elevator is 210 feet deep, and thus this is the deeper one.
Mark me Brainly answer 2/5
X + 58 = 6
x = 6 - 58
x = - 52
Answer:
Coordinates of Q ![(x_2,y_2) \:are\: \mathbf{(7,16)}](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29%20%5C%3Aare%5C%3A%20%5Cmathbf%7B%287%2C16%29%7D)
Option D is correct option.
Step-by-step explanation:
We are given:
K is the midpoint of PQ
Coordinates of P = (-9,-4)
Coordinates of K = (-1,6)
We need to find coordinates of Q
We will use the formula of midpoint: ![Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%29)
We are given midpoint K and
the coordinates of P we need to find
the coordinates of Q.
![Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\(-1,6)=(\frac{-9+x_2}{2},\frac{-4+y_2}{2})\\](https://tex.z-dn.net/?f=Midpoint%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%29%5C%5C%28-1%2C6%29%3D%28%5Cfrac%7B-9%2Bx_2%7D%7B2%7D%2C%5Cfrac%7B-4%2By_2%7D%7B2%7D%29%5C%5C)
Now, we can write
![-1=\frac{-9+x_2}{2}, 6=\frac{-4+y_2}{2}\\Simplifying:\\-2=-9+x_2\:,\: 12=-4+y_2\\-2+9=x_2\:,\: 12+4=+y_2\\x_2=7\:,\:y_2=16](https://tex.z-dn.net/?f=-1%3D%5Cfrac%7B-9%2Bx_2%7D%7B2%7D%2C%206%3D%5Cfrac%7B-4%2By_2%7D%7B2%7D%5C%5CSimplifying%3A%5C%5C-2%3D-9%2Bx_2%5C%3A%2C%5C%3A%2012%3D-4%2By_2%5C%5C-2%2B9%3Dx_2%5C%3A%2C%5C%3A%2012%2B4%3D%2By_2%5C%5Cx_2%3D7%5C%3A%2C%5C%3Ay_2%3D16)
So, we get coordinates of Q ![(x_2,y_2) \:are\: \mathbf{(7,16)}](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29%20%5C%3Aare%5C%3A%20%5Cmathbf%7B%287%2C16%29%7D)
Option D is correct option.