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vekshin1
3 years ago
6

Function tables are?

Mathematics
1 answer:
givi [52]3 years ago
8 0

Answer:

a table that describes a function by displaying inputs and corresponding outputs in tabular form

Step-by-step explanation:

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A new truck sells for $29,000 and depreciates 12% each year. Find the value of the truck after 10 years.
ozzi

Answer:

according to the question value got less 12% each year

first of all the 12% of 29000$ = 29000÷100×12= 3480 $

in one year truck value deprecates 3480$

in 10 years it will 3480$×10 =34800$

now truck cost will be = 29000-34800$= -5000$

5 0
3 years ago
Find x on this triangle
blsea [12.9K]

Answer:

3 sqrt(3) =x

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adj / hyp

cos 30 = x/6

6 cos 30 = x

6 ( sqrt(3)/2) = x

3 sqrt(3) =x

7 0
3 years ago
If you add 21 to my number and then multiply the result by 3, you will get 84 more than two-thirds of my number. Find my number.
Ksivusya [100]

Based on the calculations, the unknown number is equal to \frac{-45}{7}

  • Let the unknown number be x.

<h3>How to find an unknown number:</h3>

Translate the word problem into an algebraic expression, we have;

Adding 21 to the unknown number:

21 +x

Multiplying the result by 3:

3\times (21+x)

84 more than two-thirds of the unknown number:

\frac{2x}{3} +84

Equating the equations, we have:

3\times (21+x) = \frac{2x}{3} +84\\\\43+3x=\frac{2x}{3} +84

Cross-multiplying, we have:

43+3x=\frac{2x}{3} +84\\\\129+9x=2x+84\\\\9x-2x=84-129\\\\7x=-45\\\\x=\frac{-45}{7}

Read more on word problems here: brainly.com/question/13170908

5 0
3 years ago
Why is 1/2 not useful as a benchmark to compare 5/8 and 9/10?
pentagon [3]
1/2 would not be a useful benchmark to compare these 2 fractions because both of them are greater than half. The benchmark fraction 1/2 is most useful when one fraction is less than half and the other more than 1/2. 5/8 is more than 4/8(1/2), and 9/10 is more than 5/10(1/2).
4 0
3 years ago
Read 2 more answers
Suppose y varies directly as x², and y = 160 when x = 4. Find y when x = 6.
labwork [276]

<u>Finding the constant of proportionality</u> :

  • y = kx²
  • 160 = k(4)²
  • k = 10

<u>Finding y when x = 6</u> :

  • y = 10(6)²
  • y = 10(36)
  • y = 360

The value of y is <u>360</u> when x = 6.

7 0
2 years ago
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