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3 years ago

13.225 + 2.6 what is the answer to that question

Mathematics

2 answers:

devlian [24]3 years ago

8 0

15.825 , your basically adding it up regularly instead you add a decimal !

grin007 [14]3 years ago

7 0

15.825 would be the answer to this

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Which of the following expressions results in a positive number?

arlik [135]

Answer:

-30(-8)

Step-by-step explanation:

A negative times a negative always equals a positive.

6 0

3 years ago

Read 2 more answers

HELP!!!!!!!!!!!!!!!!!!!!

solong [7]

Answer:

y = -1/2x+4

Step-by-step explanation:

y = 2x-1

This equation is in slope intercept form y = mx+b where m is the slope

m=2

A line perpendicular will have a slope that is the negative reciprocal

m = -1/2

Using the slope intercept form

y = mx+b

y = -1/2x+b

and the point given (2,3)

3 = -1/2(2)+b

3 = -1+b

4 =b

y = -1/2x+4 is the equation of a line that is perpendicular to the original line and contains (2,3)

6 0

2 years ago

3. company pays a greater annual salary? Show your Company A offers a semimonthly salary of $2432, and Company B offers a biweek

Eduardwww [97]

Company A offer
2,432×24(semimonthly)
=58,368 per year

Company B offer
2,390×26 (biweekly)
=62,140 per year

So company B pays a greater annual salary

Hope it helps!

5 0

3 years ago

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So $\mu = 375, \sigma = 68$

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So $n = 6, s = \frac{68}{\sqrt{6}} = 27.76$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 375}{27.76}$

$Z = 1.26$

$Z = 1.26$ has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So $\mu = 522, \sigma = 106$