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2 years ago

What are the domain and range of the function

Mathematics

1 answer:

Korvikt [17]2 years ago

6 0

Answer:

Domain: (-∞,∞)

Range: (-∞,∞)

Step-by-step explanation:

The x variable can take any value, because the function does not have any restriction.

The range of the function is the same because this is a polynomical function.

You might be interested in

What is the percentage of this

dexar [7]

Answer:

69%

Step-by-step explanation:

10×10 table, 69 cells are orange. Therefore the fraction 69/100 as a percentage is 69%.

4 0

1 year ago

A lottery has 60 numbers. To win the jackpot one needs to match all 7 numbers that are drawn by the machine. Is this a PERMUTATI

Vadim26 [7]

Answer: Hence, our required probability is $\dfrac{1}{386206920}$

Step-by-step explanation:

Since we have given that

Numbers in a lottery = 60

Numbers to win the jackpot = 7 numbers

We need to find the probability to hit the jackpot:

So, our required probability is given by

$P=\dfrac{^7C_7}{^{60}C_7}\\\\P=\dfrac{1}{386206920}$

This is a combination problem as we need to select 7 numbers irrespective of any arrangements.

Hence, our required probability is [tex]\dfrac{1}{386206920}[/tex

4 0

2 years ago

If we sub (3x-5y) from (6x +8y)then the result is plz repy

konstantin123 [22]

Answer:

3x + 13y

Explanation:

6x + 8y − (3x − 5y)

Distribute the Negative Sign

6x + 8y + −1(3x − 5y)

6x + 8y + −1(3x) + −1(−5y)

6x + 8y + −3x + 5y

Combine Like Terms

6x + 8y + −3x + 5y

(6x + −3x) + (8y + 5y)

= 3x + 13y

8 0

2 years ago

Read 2 more answers

Your middle school has 900 students one third of the students bring their lunch instead of buying your lunch at school what is t

r-ruslan [8.4K]

1/3 of all students bring lunch
2:3 is the ratio of students who bring their lunch to the number of students who do not

7 0

2 years ago

Assume that women's heights are normally distributed with a mean given by mu equals 62.5 in,and a standard deviation given by

Misha Larkins [42]

Answer:

(a) 0.5899

(b) 0.9166

Step-by-step explanation:

Let X be the random variable that represents the height of a woman. Then, X is normally distributed with

$\mu$ = 62.5 in

$\sigma$ = 2.2 in

the normal probability density function is given by

$f(x) = \frac{1}{\sqrt{2\pi}2.2}\exp{-\frac{(x-62.5)^{2}}{2(2.2)^{2}}}$ , then

(a) $P(X < 63) = \int\limits_{-\infty}^{63}f(x) dx$ = 0.5899

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2)

(b) We are seeking $P(\bar{X} < 63)$ where n = 37. $\bar{X}$ is normally distributed with mean 62.5 in and standard deviation $2.2/\sqrt{37}$ . So, the probability density function is given by

$g(x) = \frac{1}{\sqrt{2\pi}\frac{2.2}{\sqrt{37}}}\exp{-\frac{(x-62.5)^{2}}{2(2.2/\sqrt{37})^{2}}}$ , and

$P(\bar{X} < 63) = \int\limits_{-\infty}^{63}g(x)dx$ = 0.9166

(in the R statistical programming language) pnorm(63, mean = 62.5, sd = 2.2/sqrt(37))

You can use a table from a book to find the probabilities or a programming language like the R statistical programming language.

4 0

2 years ago