What are the domain and range of the function

Mathematics

1 answer:

Korvikt [17]2 years ago

6 0

Answer:

Domain: (-∞,∞)

Range: (-∞,∞)

Step-by-step explanation:

The x variable can take any value, because the function does not have any restriction.

The range of the function is the same because this is a polynomical function.

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Mr. Anderson drove 168 miles in 3 hours. He then drove the next 2 hours at a rate

Luda [366]

Answer:

If you were asking how many miles in total: 290 miles.

If you were asking how many miles in the 2 hours: 122 miles

Step-by-step explanation:

In the first 168 miles,

$Since \\v_1=168miles/3h=56 miles/h\\\\Thus \\v_2=v_1+5=56+5=61miles/h\\\\X_1=168miles\\X_2=v_2*2h=61*2=122miles\\X_1+X_2=168+122=290miles\\\\$

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2 years ago

Help me please 2. You learn from your science teacher that water expands when you freeze it. The next time that you freeze your

harkovskaia [24]

You would be correct. Direct reasoning you already have your teacher who told you what would happen you are simply doing a reaction because of her.

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2 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

Slope:

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

Slope:

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$