All categories

3 years ago

How to find the median

2 answers:

3 0

We can find the median by using the formula:

(N+1/2) th item

For example:

Given data: 4,6,3,5,7

We have to arrange the data into ascending order:

=3,4,5,6,7

N(total no of items)=5

Now,

Median=(N+1/2)th item

 =(5+1/2) th item

 =(6/2) th item

 = 3rd item

Median=5

Hope it helps

Good luck on your assignment

Anit [1.1K]3 years ago

3 0

To find the median, put all numbers into ascending order and work into the middle by crossing off numbers at each end. If there are a lot of items of data, add 1 to the number of items of data and then divide by 2 to find which item of data will be the median

You might be interested in

What is the quatient of (×3+6×2+11×+6)÷(×2+4×+3

lapo4ka [179]

Answer:

=21+11x

Step-by-step explanation:

3 0

4 years ago

Type the verb form suggested by the related word(s). exerciser

loris [4]

Answer:

exercising

Step-by-step explanation:

8 0

4 years ago

<img src="https://tex.z-dn.net/?f=4x%5E%7B0%7D%20x16x%5E%7B0%7D" id="TexFormula1" title="4x^{0} x16x^{0}" alt="4x^{0} x16x^{0}"

statuscvo [17]

Answer:

Step-by-step explanation:

its just how it is

8 0

3 years ago

Which of the equations below represents a line perpendicular to the x-axis?

Allushta [10]

Answer:

Option B

Step-by-step explanation:

we know that

A line perpendicular to the x-axis is a line parallel to the y-axis

the equation of the line is of the form x=(+/-)a

The slope of the line is undefined

where

a is a real number

therefore

x=6 is a line perpendicular to the x-axis

5 0

3 years ago

Read 2 more answers

Can someone please explain me this

Vlad [161]

1st way

To solve this we need to know ratio.

$- \frac{1}{5} \div \frac{1}{5} = - 1 \\$

Now we can see that odd numbers of geometric sequence are positive and even numbers are negative. 91 - odd number, so it will be positive. If ratio is equal to -1, than 91st number is

$\frac{1}{5} \\$

2nd way

Firstly, we need to find ratio.

$- \frac{1}{5} \div \frac{1}{5} = - 1 \\$

Secondly, we need to use this formula

$b_n=b_1 \times q^{n-1} \\$

$b_{91}= \frac{1}{5} \times ( - 1)^{91-1} = \frac{1}{5} \\$

6 0

3 years ago