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2 years ago

15

Imagine this like a fraction top:36+kt bottom: 36- 4kt. k=2. t=3

1 answer:

Gelneren [198K]2 years ago

6 0

Top:
36 + 2(3)
36 + 6
☆42
bottom:
36 - 4(2)(3)
36 - 24
☆12

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Tom begins his morning shift at 9:45

Murrr4er [49]

9:45 plus 3 hours goes to 12:45 pm. add 45 minutes you get 1:30PM as your answet

6 0

3 years ago

Find each measure cause i don't understand?

vekshin1

Answer:

x=6 . m<PQS=82 m<SQR=61 :)

Step-by-step explanation:

(13x+4) + (10x-1) = 141

combine like terms

23x+3=141

subtract 3 from both sides

23x=138

divide both sides by 23

x=6

substitute x into both original equations

m<PQS=13(6)+4

m<PQS=78+4

m<PQS= 82

m<SQR=10(6)+1

m<SQR=60+1

M<SQR=61

4 0

2 years ago

Read 2 more answers

Which means the sum of w and 3.4 is greater than or equal to 10.5

mr_godi [17]

It states "greater than or equal", therefore, you will have to use a sign which has equal in it.
w + 3.4 ≥ 10.5

5 0

3 years ago

A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are C(x)=72,000+60x

myrzilka [38]

Answer:

Step-by-step explanation:

Given

Cost Price $c(x)=72000+60x$

Price $p(x)=300-\frac{x}{20}$

Revenue generated $R(x)=P(x)\times x$

where x=no of units

$R(x)=300x-\frac{x^2}{20}$

To get maxima and minima differentiate R(x)

$\frac{\mathrm{d} R(x)}{\mathrm{d} x}=0$

$\frac{\mathrm{d} R(x)}{\mathrm{d} x}=300-2\times \frac{x}{20}=0$

$300=2\times \frac{x}{20}$

$x=3000$

maximum Revenue $R(x)=(300-\frac{300}{20})\times 300=4,50,000$

(b)Profit=Revenue - cost

$Profit=xp(x)-c(x)$

$Profit=300x-\frac{x^2}{20}-72000-60x$

$Profit(z)=240x-\frac{x^2}{20}-72000$

differentiate Profit to get maximum value

$\frac{\mathrm{d} z}{\mathrm{d} x}=240-2\times \frac{x}{20}$

$x=2400$

maximum Profit $z=2,16,000$

(c)Now company decided to tax the company $ 55 for each set

Profit $(z_1)=xp(x)-c(x)-55x$

$z_1=300x-\frac{x^2}{20}-72000x-60x^2-55x$

$z_1=185x-\frac{x^2}{20}-72,000$

differentiate Profit to get maximum value

$\frac{\mathrm{d} z_1}{\mathrm{d} x}=0$

$\frac{\mathrm{d} z_1}{\mathrm{d} x}=185-\frac{2x}{20}=0$

$x=1850$

$P(z_1\ at\ x=1850)=99125$

company should charge 207.5 $ for each set

6 0

3 years ago

Refer to the data set of body temperatures in degrees Fahrenheit given in the accompanying table and use software or a calculato

Mariulka [41]

The mean of the dataset is the average, while the median is the middle element.

<em>The mean and the median of the given dataset is 98.2</em>
<em>The results support the common belief that the mean body temperature is 98.6F</em>

<em />

The mean of the dataset is calculated using:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{99.2+ 99.2 +98.2+............+97.7}{48}$

$\bar x = \frac{4715}{48}$

$\bar x = 98.2$

The median position is:

$Median = \frac{1}{2}(n + 1)$

$Median = \frac{1}{2}(48 + 1)$

$Median = \frac{1}{2}(49)$

$Median = 24.5$

This means that the median is the average of the 24th and 25th element

Using the sorted dataset, we have:

$Median = \frac{1}{2}(98.2 + 98.2)$

$Median = 98.2$

<em>Because the calculated mean and the common belief (98.6) are close, then we can conclude that the results support the common belief that the mean body temperature is 98.6F</em>

<em />

Read more about mean and median at:

brainly.com/question/17060266

7 0

2 years ago