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Darina [25.2K]
4 years ago
5

Two squares are drawn. The larger Square has area of 400 in.². The area of the two squares have a ratio of 1 to 4. What is the s

ide length S of the smaller square?
Mathematics
1 answer:
Alex Ar [27]4 years ago
8 0
The first thing we must do in this case is to find the area of the smallest square.
 For this, we use the following relationship:
 A1 / A2 = 4/1
 Substituting:
 400 / A2 = 4/1
 From here, we clear A2:
 A2 = (1/4) * (400)
 A2 = 100 in ^ 2
 We now look for the side of the small square, we use the following relationship:
 A = S ^ 2
 We cleared S:
 S = root (A)
 S = root (100)
 S = 10 in
 Answer:
 the side length S of the smaller square is:
 S = 10 in
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Angle a and b are supplementary angles. If m a = (x – 40)0 and m b = (x + 20)0, find the value of x, m a and m b
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∠ a = 60° , ∠ b = 120°

Step-by-step explanation:

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3x + 25 + 7x - 19 = 10x - 6

Set them equal to each other

∠ABF = ∠CBE

6x + 26 = 10x - 6

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6x (-6x) + 26 (+6) = 10x (-6x) - 6 (+6)

26 + 6 = 10x - 6x

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32 = 4x

Divide 4 from both sides

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Plug in 8 for x

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74° is your answer for m∠F

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4 0
3 years ago
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