The y intercept is where the line hits the verticals line of the graph. Hope this helps!
Length(l)= 2w
width(w)= w
Perimeter(P)= 2w+2l= 72 (simplify expression: divide each side by 2 )
P= w+l= 36 (plug in "2w" for "l")
P= w+(2w)= 36
P= 3w= 36 (divide each side by 3 to find the width)
w= 12 units
find length:
l=2w
l= 2(12)
l= 24 units
Answer:
The length of this rectangle is 24 units and the width is 12 units.
This is the graph for the equation, it crosses through points (0,-8) (-2,4) (-1.6,0) and its vertex is (-2,2)
Hope this helps !!
Answer:
Option A is correct.
The value of r = -0.7 represents the strongest negative correlation.
Step-by-step explanation:
A correlation is a value that describes a relationship between two things or variables.
Strongest Negative Correlation says that closer a negative correlation to -1, the stronger the relationship between the two variables.
From the options, we have only two negative values i.e, r= -0.7 and r= -0.22.
We have to find the strongest negative correlation r-value.
By the definition, you can see that -0.7 is very closer to -1 ,
therefore, the value of r = -0.7 represents the strongest negative correlation.
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.
What is the theoretical probability that the family has two dogs or two cats?
25% chance
</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa).
<span>3. Flip both coins 50 times and record your data in a table like the one below.
</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance
<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?
1/8 chance (accidentally messed up there) or 12.5%
</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.
I hope that this helps because it took a while to write out. If it does, please rate as Brainliest
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