Hey there!
The answer to your question is 
Write the equation
Distribute -2
Combine like terms
Add 10 to both sides
Divide both sides by -11
Hope it helps and have a great day!
The correct answer to this question would be answer choice B.
To convert the decimal 0.56 to a fraction, first set it to a fraction over 100 which would be 56/100.
Then, because the question asks for the fraction to be in simplest form, look for the greatest common factor of the numerator and denominator or 56 and 100.
To find it, list out all of their factors:
56: 1, 2, 4, 7, 8 , 14, 28, 56
100: 1, 2, 4, 5, 10,20,25,50,100
Notice that out of all the factors listed, the greatest common factor listed is 4. Because of this, divide both the numerator and denominator by 4 to simplify your fraction to your answer: 14/25
The measure of the unknown angles in the kite are as follows;
- x = 66 degrees
- y = 158 degrees
<h3>How to find the measure of a kite?</h3>
A kite has two pairs of adjacent equal sides.
In other words, a kite is a quadrilateral that has 2 pairs of equal-length sides and these sides are adjacent to each other.
One pair of opposite angles is equal. Diagonals are perpendicular to each other.
A kite has four interior angles and the sum of these interior angles is 360°
Therefore, the measures of the
x = 66 degrees.
Let's find y.
y = 360 - 70 - 66 - 66
y = 158 degrees.
learn more on kites here: brainly.com/question/24263475
#SPJ1
The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
Answer:
ehhh- i give up
Step-by-step explanation:
