Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
4x+2y<=16
3x+3y<=15
2x+y<=8
x+y<=5
3x+2y->maximize profit
X Y profit
1 4 11
2 3 12
3 2 13
4 0 12
3 1 11
3 2 13
2 3 12
1 4 11
0 5 10
Farmer need to make 3 Apple pies and 2 apple cobblers
Farmer will use 16 cups of apples and 15 cups of flour
profit of farmer will be $13
Answer:
No, he is not correct because the constant in his answer should have been 21 not 7.
Step-by-step explanation:
Therefore, the correct answer is the fourth; he should have put 21.
Answer:
wait can u send the screen shot again it wont load.
Step-by-step explanation:
