18 because that’s the greatest common factor for all of them
we know that
The measurement of the exterior angle is the semi-difference of the arcs which comprises
In this problem
∠FGH is the exterior angle
∠FGH=
∠FGH=
-----> equation A

--------> equation B
Substitute equation B in equation A
![100\°=(arc\ FEH-[360\°-arc\ FEH])](https://tex.z-dn.net/?f=100%5C%C2%B0%3D%28arc%5C%20FEH-%5B360%5C%C2%B0-arc%5C%20FEH%5D%29)



therefore
<u>The answer is</u>
The measure of arc FEH is equal to 
The length of that arc is (90/360)·2·π·6 = (1/4)·12·π = 3·π ≈ 9.42 units;
Answer:
Q=33/10-r/10 R=33−10q
Step-by-step explanation:
Espero que sea correcto para ti también puedes hacerme más inteligente si es correcto
Answer:
44
Step-by-step explanation:
fx=6(8)-4
fx=48-4
fx=44