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BigorU [14]
3 years ago
7

I need help on this problem I have 6 minutes left to solve this!.”

Mathematics
2 answers:
kogti [31]3 years ago
6 0
I think its 7 because if you take the full amount of the one side (12) and subtract it by 5 then you get 7 i hope this helped!!
Elenna [48]3 years ago
4 0
The answer is 6
Hope this helps :)
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Lyrx [107]

it is 40.5 because area equals base times height.

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3 years ago
Which expresion means the same as 2 1/5
Mandarinka [93]
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3 years ago
An elevator has weight limit of 1 ton. There are 3 people inside the elevator. Each person weighs 150 pounds. How many pounds ca
drek231 [11]

Answer:

2000 Pounds

Step-by-step explanation:

There are 2000 pounds in a US ton.

There are 2240 pounds in an Imperial ton.

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7 0
3 years ago
Suppose that we wish to assess whether more than 60 percent of all U.S. households in a particular income class bought life insu
IceJOKER [234]

Answer:

A. 0.0049

B. Yes

Step-by-step explanation:

Sample proportion = 0.64

N = 1000

Population proportion = 0.60

We solve for standard deviation

= √p(1-p)/n

= √0.60(1-0.60)/1000

= √0.60x0.40/1000

= √0.00024

= 0.0155

A.

The probability of sample >=0.64

Z>=0.64-0.60/0.0155

Z >= 0.04/0.0155

So z >= 2.5806

Using excel this equal to 0.0049

0.0049 is probability of sample proportion being 0.64 at least.

B.

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3 0
2 years ago
According to the "January theory," if the stock market is up for the month of January, it will be up for the year. If it is down
PSYCHO15rus [73]

Answer:

The required probability is 0.031918.

Step-by-step explanation:

Consider the provided information.

It is given that According to an article in The Wall Street Journal, this theory held for 22 out of the last 34 years.

Therefore n=34

The probability it is either up or down is 0.5.

Thus the value of p =0.5 and q = 0.5

Now calculate the probability

Let X is the number of years that theory held.

X has a binomial distribution with n=34 and p=0.5

P(X=22)=\binom{34}{22}(0.5)^{22}(0.5)^{12}\\P(X=22)=\frac{34!}{22!\times 12!}(0.5)^{22}(0.5)^{12}\\P(X=22)=548354040\times 5.8207660913\times 10^{11}\\P(X=22)=0.0319184060208\\P(X=22)\approx0.031918

Hence, the required probability is 0.031918.

8 0
3 years ago
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