Question

Simplify 6 to the fifth power over 7 cubed all raised to the second power. 6 to the seventh power over 7 to the tenth power 6 to the tenth power over 7 to the sixth power 6 cubed over 7 12 to the fifth power over 14 cubed

Answer 1

$\left( \cfrac{6^5}{7^3}\right )^2=\cfrac{(6^5)^2}{(7^3)^2}=\cfrac{6^{5*2}}{7^{3*2}}=\cfrac{6^{10}}{7^6}$

Answer 2

Answer:

6 to the tenth power over 7 to the sixth power

Step-by-step explanation:

Given phrase,

6 to the fifth power over 7 cubed all raised to the second power,

$\implies (\frac{6^5}{7^3})^2$

By using $(a^m)^n=a^{mn}$

$=\frac{6^{5\times 2}}{7^{3\times 2}}$

$=\frac{6^{10}}{7^6}$

= 6 to the tenth power over 7 to the sixth power