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rusak2 [61]
3 years ago
6

Simplify 6 to the fifth power over 7 cubed all raised to the second power. 6 to the seventh power over 7 to the tenth power 6 to

the tenth power over 7 to the sixth power 6 cubed over 7 12 to the fifth power over 14 cubed
Mathematics
2 answers:
Phantasy [73]3 years ago
8 0
\left( \cfrac{6^5}{7^3}\right )^2=\cfrac{(6^5)^2}{(7^3)^2}=\cfrac{6^{5*2}}{7^{3*2}}=\cfrac{6^{10}}{7^6}
kobusy [5.1K]3 years ago
5 0

Answer:

6 to the tenth power over 7 to the sixth power

Step-by-step explanation:

Given phrase,

6 to the fifth power over 7 cubed all raised to the second power,

\implies (\frac{6^5}{7^3})^2

By using (a^m)^n=a^{mn}

=\frac{6^{5\times 2}}{7^{3\times 2}}

=\frac{6^{10}}{7^6}

= 6 to the tenth power over 7 to the sixth power

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