Answer:
Keith's unit rate of change of dollars with respect to time is $1500.
Step-by-step explanation:
It is given that Keith is saving money for a car.
Year 1: 1500
year 2: 3000
year 3: 4500
Let y be the saved amount after x year.
The coordinate pairs according to the given table are (1,1500), (2,3000) and (3,4500).
The formula for rate of change is
Consider any two coordinate pairs.
Let as consider (1,1500) and (2,3000). So, Keith's unit rate of change of dollars with respect to time is
Therefore, Keith's unit rate of change of dollars with respect to time is $1500.
If 28 is the distance that he is from the starting point then
so 10 to the right
+10
then 3 to the left
-3powerjump
10-3pj
total jump length must be to the left because 10 is less than 28 and he can't jump negative feet
absolute value
|10-3p|=28
since we assume that he jumped 28 feet to the left, we can assuume
10-3p=-28
subtract 10 from both sides
-3p=-38
divide by -3
powerjump=12 2/3
or if the problem is he jumped 28 feet in total then
10+3p=28
subtract 10 from both sdies
3p=18
divie by 3
powerjump=6
1) / sin x / = y ≥ 0 ;
We solve the equation
a = 1 ; b = 1 ; c = - 2 ;
y1 = ( - 1 + 3 ) / 2 = 1 ≥ 0 ( correct ) ;
y2 = ( - 1 - 3 ) / 2 = - 2 ≥ 0 ( false ) ;
Then, / sin x / = 1 ;
sinx = + 1 or sin x = - 1 ;
x ∈ { 90 } U { 270 } ;
x ∈ {90 , 270}.
