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Kobotan [32]
3 years ago
11

Can someone help? ( I need it by 10/20)

Mathematics
1 answer:
Hoochie [10]3 years ago
4 0
<h3>Answer:  x = 12</h3>

=====================================================

Explanation:

C is the midpoint of AB. This means AC is half as long as AB

Put another way, AB is twice as long as AC

AB = 2*AC

AB = 2*( AC )

32 = 2*( x/2 + 10 )  .... substitution

32 = 2*(x/2) + 2*10 ... distribute

32 = x + 20

x+20 = 32

x = 32-20 .... subtract 20 from both sides

x = 12

---------

If x = 12, then

AC = x/2 + 10

AC = 12/2 + 10

AC = 6+10

AC = 16

which is half of AB = 32, so it confirms our answer.

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A substantial portion of inventory owned by Prentiss Sporting Goods was recently destroyed when the roof collapsed during a rain
kkurt [141]

Answer:

a) $150,225

b) $450,675

c) $152,425

d) $17,700

Step-by-step explanation:

Given:

Beginning inventory = $204,300

Purchases to date of storm = $398,800

Sales to date of storm = $600,900

The value of undamaged inventory counted = $134,725

Prentiss’s gross margin percentage = 25% of sales

a) Now,

Gross margin = Sales × Gross margin percentage

= $600,900 × 25%

= $150,225

GROSS MARGIN ( DOLLARS)= 113506

b) Cost of goods sold = Sales - Gross margin

= $600,900 - $150,225

= $450,675

c) Ending inventory

= Beginning inventory + purchase - Cost of goods sold

= $204,300  + $398,800  - $450,675

= $152,425

d) Amount of lost inventory

= Ending inventory - Undamaged inventory

= $152,425 - $134,725

= $17,700

5 0
3 years ago
It costs $70 for 50 tickets. How much does each ticket cost?
liberstina [14]
1 dollar and 40 cents
5 0
3 years ago
Read 2 more answers
Apply division algorithm to find the quotient and remainder on dividing the polynomial 3 x^ + 4 x^ square + 6 x + 9 by x^ + 3x +
Ulleksa [173]

I suppose you mean

\dfrac{3x^3+4x^2+6x+9}{x^2+3x+7}

3x^3=3x\cdot x^2, and if we multiply x^2+3x+7 by 3x we get 3x^3+9x^2+21x. Subtracting this from the numerator gives a remainder of -5x^2-15x+9.

-5x^2=-5\cdot x^2, and multiplying x^2+3x+7 by -5 gives -5x^2-15x-35. Subtracting this from the previous remainder gives a new remainder of 44.

44 has no remaining factors of x^2 in it, so we're done, and

\dfrac{3x^3+4x^2+6x+9}{x^2+3x+7}=\underbrace{3x-5}_{\rm quotient}+\dfrac{\overbrace{44}^{\rm remainder}}{x^2+3x+7}

4 0
4 years ago
7 + 3 (2x - 5) = 3x + 7
monitta
X=5 because this same question was in my test and I got it right
5 0
3 years ago
Read 2 more answers
Find the x-intercepts of the parabola with<br> vertex (1,20) and y-intercept (0,16).
Wewaii [24]

Answer:

Step-by-step explanation:

Since we are finding the x-intercepts, that implies that this is a parabola that opens either up or down as opposed to right or left. It would benefit us to know the equation of the parabola so we could factor it to find the roots (which are also known as the x-intercepts).

Here's what we know:

h = 1, k = 20, x = 0, and y = 20. Filling in the vertex form of a parabola is already halfway to factored, so we'll use that format as opposed to the standard form, which is

y=ax^2+bx+c. The vertex form is

y=a(x-h)^2+k and filling in our values from above:

16=a(0-1)^2+20 and

16=a(1)+20 and

-4 = a. So the equation for the parabola is

y=-4(x-1)^2+20. Now set it equal to 0 and factor.

-20=-4(x-1)^2 and divide both sides by -4 to get:

5=(x-1)^2 and take the square root of both sides to get

±\sqrt{5}=x-1 and then add 1 to both sides to get the x-intercepts (or roots or solutions or zeros...they're all the same).

x = 1 ±√5 and you're done!

3 0
3 years ago
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