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Kobotan [32]
3 years ago
11

Can someone help? ( I need it by 10/20)

Mathematics
1 answer:
Hoochie [10]3 years ago
4 0
<h3>Answer:  x = 12</h3>

=====================================================

Explanation:

C is the midpoint of AB. This means AC is half as long as AB

Put another way, AB is twice as long as AC

AB = 2*AC

AB = 2*( AC )

32 = 2*( x/2 + 10 )  .... substitution

32 = 2*(x/2) + 2*10 ... distribute

32 = x + 20

x+20 = 32

x = 32-20 .... subtract 20 from both sides

x = 12

---------

If x = 12, then

AC = x/2 + 10

AC = 12/2 + 10

AC = 6+10

AC = 16

which is half of AB = 32, so it confirms our answer.

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Write 0.397 as a fraction in simplest form.
e-lub [12.9K]

Answer:

397/1000

Step-by-step explanation:

Mark ‼️ it brainliest if it helps you ❤️

7 0
2 years ago
Sandy has 27 roses, 9 daisies, and 18 tulips. She wants to arrange all the flowers in bouquets. Each bouquet has the same number
AlekseyPX

Answer:

The greatest number of flowers that could be in a bouquet is 9 flowers

Step-by-step explanation:

We solve the above question using Greatest Common Factor method. We find the factors of 27, 9 and 18. The greatest factor common to the 3 number is our answer.

The factors of 9 are: 1, 3, 9

The factors of 18 are: 1, 2, 3, 6, 9, 18

The factors of 27 are: 1, 3, 9, 27

Then the greatest common factor is 9.

The greatest number of flowers that could be in a bouquet is 9 flowers

5 0
3 years ago
Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx
Feliz [49]
Your question seems a bit incomplete, but for starters you can write

\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}

Expanding where necessary, recalling that (1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x, you have

\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x

Now, since 1+\tan^2x=\sec^2x, the final form could also take

\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1

or

\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x
7 0
3 years ago
6. Sketch the region enclosed by the graphs of x =0, 6y-5x=0 and x+3y=21. Find the area
kow [346]
We can see that revolving the region formed by intersecting 3 lines, we will get 2 cones that are connected their bases.
Volume of the cone V=1/3 *πr²*h

1) small cone has r=5, and h=5
Volume small cone V1= 1/3 *π*5²*5 = 5³/3 *π
2) large cone has r=5, and h=21-6=15, h=15
Volume large cone V2= 1/3 *π*5²*15 = 5³*π
3) whole volume
5³/3 *π + 5³*π=5³π(1/3+1)=((5³*4)/3)π=(500/3)π≈166.7π≈523.6

Area
we see 2 right triangles,
Area of the triangle=1/2*b*h, where b -base, h -height
1) small one, b=5, h=5
A1=(1/2)*5*5=25/2
2)large one, b=5, h=15
A2=(1/2)*5*15=75/2
3) whole area=A1+A2=25/2+75/2=100/2=50

3 0
3 years ago
Read 2 more answers
Someone help lolz..​
Mkey [24]
The answer is y =-4 !
6 0
2 years ago
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