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3 years ago

If 10% of a number is 8, what is 50% of the number?

Mathematics

2 answers:

Over [174]3 years ago

7 0

Answer:

50% of the number is 40

Step-by-step explanation:

8 * 5 = 40

lora16 [44]3 years ago

5 0

Answer:

10/100 x=8

10x=800

x=8

50/100 x 8

1/2 x 8

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F(n)=4n <br> g(n)=n2+2n <br> find f(g(-6))

ELEN [110]

Answer:

When f(n) = 4n and g(n) = n² + 2n, f(g(-6)) = 96.

Step-by-step explanation:

To evaluate f(g(-6)), first find g(-6).

g(n) = n² + 2n

Substitute value.

g(-6) = (-6)² + 2(-6)

Square -6. Remember that (-x)² = x²

g(-6) = 36 + 2(-6)

Multiply 2 and -6.

g(-6) = 36 - 12

Subtract 12 from 36.

g(-6) = 24.

Now knowing this, substitute that value into f(n).

f(g(-6)) = f(24)

f(n) = 4n

Substitute value.

f(24) = 4(24)

Multiply 4 and 24.

f(24) = 96.

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2 years ago

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3 years ago

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MAVERICK [17]

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3 years ago

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3 years ago

Question 3 (1 point) Co-60 has a half life of 5.3 years. If a pellet that has been in storage for 26.5 years contains 14.5g of C

Zarrin [17]

Answer:

464 grams.

Step-by-step explanation:

Amount of substance:

The amount of substance after t years is given by an equation in the following format:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Co-60 has a half life of 5.3 years.

This means that:

$A(5.3) = 0.5A(0)$

We use this to find r. So

$A(t) = A(0)(1-r)^t$

$0.5A(0) = A(0)(1-r)^{5.3}$

$(1-r)^{5.3} = 0.5$

$\sqrt[5.3]{(1-r)^{5.3}} = \sqrt[5.3]{0.5}$

$1 - r = 0.5^{\frac{1}{5.3}}$

$1 - r = 0.8774$

$A(t) = A(0)(0.8774)^{t}$

If a pellet that has been in storage for 26.5 years contains 14.5g of Co-60, how much of this radioisotope was present when the pellet was put in storage?

We have that $A(26.5) = 14.5$ , and use this to find A(0). So

$A(t) = A(0)(0.8774)^{t}$

$14.5 = A(0)(0.8774)^{26.5}$

$A(0) = \frac{14.5}{(0.8774)^{26.5}}$

[tex]A(0) = 464[tex]

464 grams.

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3 years ago