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3 years ago

Factor this trinomial. x2 - 8x+15

Mathematics

2 answers:

Jobisdone [24]3 years ago

6 0

Answer:

(x-3)(x-5)

Step-by-step explanation:

The expression is:

x2 - 8x+15

Break the middle term:

Coefficient of first term will be multiplied by constant

1*15 = 15

Now we have to find out which numbers will be multiplied to get 15

and also by adding those numbers we get the middle term:

3*5=15

3+5 = 8

Now break the middle term:

x^2-3x-5x+15

x(x-3)-5(x-3)

(x-5)(x-3)....

The factors are (x-5)(x-3)....

kupik [55]3 years ago

4 0

Answer:

(x - 5)(x - 3)

Step-by-step explanation:

You need two numbers that multiply to 15 and add to 8. There aren't many numbers that will do that.

15 and 1 is one pair of numbers. They multiply to 15 but don't add to 8.

6 and 2 add to 8 but don't multiply to 15.

5 and 3. This in some form is your answer, but handle it carefully.

(x - 5)(x - 3)

The 5 and 3 both have to be minus.

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If M is the centroid of triangle GHI, HL=45, JI=63, and KG=60, find the missing measures

AysviL [449]

Answer:

Part a) $ML=15\ units$

Part b) $HM=30\ units$

Part c) $JM=21\ units$

Part d) $MI=42\ units$

Part e) $GM=40\ units$

Part f) $MK=20\ units$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

A centroid of a triangle is the point where the three medians of the triangle meet. A median of a triangle is a line segment from one vertex to the mid point on the opposite side of the triangle.

The centroid is located two thirds of the distance from any vertex of the triangle

Part a) Find ML

we have

$HL=45\ units$

we know that

$ML=\frac{1}{3}HL$

substitute the given value

$ML=\frac{1}{3}(45)$

$ML=15\ units$

Part b) Find HM

we have

$HL=45\ units$

we know that

$HM=\frac{2}{3}HL$

substitute the given value

$HM=\frac{2}{3}(45)$

$HM=30\ units$

Part c) Find JM

we have

$JI=63\ units$

we know that

$JM=\frac{1}{3}JI$

substitute the given value

$JM=\frac{1}{3}(63)$

$JM=21\ units$

Part d) Find MI

we have

$JI=63\ units$

we know that

$MI=\frac{2}{3}JI$

substitute the given value

$MI=\frac{2}{3}(63)$

$MI=42\ units$

Part e) Find GM

we have

$KG=60\ units$

we know that

$GM=\frac{2}{3}KG$

substitute the given value

$GM=\frac{2}{3}(60)$

$GM=40\ units$

Part f) Find MK

we have

$KG=60\ units$

we know that

$MK=\frac{1}{3}KG$

substitute the given value

$MK=\frac{1}{3}(60)$

$MK=20\ units$

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