Answer:
1 / (x-2)(x+3)
Step-by-step explanation:
Given in the question the expression:
(x + 1) / (x² + x - 6) ÷ (x² + 5x + 4) / (x+4)
factorisation of (x² + x - 6) = (x-2)(x+3) by using quadratic equation
(x + 1) / (x-2)(x+3) ÷ (x² + 5x + 4) / (x+4)
Taking reciprocal to convert ÷ into ×
(x + 1) / (x-2)(x+3) x (x+4) / (x² + 5x + 4)
factorisation of (x² + 5x + 4) = (x+1)(x+4) by using quadratic equation
(x + 1) / (x-2)(x+3) x (x+4) / (x+1)(x+4)
cancel (x + 1) from both expression
1 / (x-2)(x+3) x (x+4) / (x+4)
cancel (x+4)
1 / (x-2)(x+3) Simplified form
Answer:
Hence, data does not suggest the true average gap detection threshold for CTS subjects exceeds that for normal subjects.
Step-by-step explanation:
H0 : μ1 = μ2
H1 : μ1 < μ2
Given :
m = 8 ; x1 = 1.71 ; s1 = 0.53
n = 10 ; x2 = 2.53 ; s2 = 0.87
The test statistic :
(x1 - x2) / √(s1²/m + s2²/n)
(1.71 - 2.53) / √(0.53²/8 + 0.87²/10)
-0.82 / √0.1108025
Test statistic = - 0.82 / 0.3328700
Test statistic = - 2.463
The degree of freedom using the conservative approach :
Smaller of (10 - 1) or (8 - 1)
df = 7
TCritical value(0.01, 7) = 2.998
Decision region :
Reject H0 if |Test statistic| > |critical value|
Since, 2.463 < 2.998 ; WE fail to reject H0 ; Hence result is not significant at α = 0.01
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brainiest? :)
Step-by-step explanation:
Given
slope (m) = - 2/ 3
Y-intercept (c) = - 4
Now writing in Slope intercept form
y = mx + c
y =( - 2/3) x - 4
Hope it will help :)