Question

The average of four different positive integers is 9. What is the greatest value for one of the integers?

Answer 1

From the given information; Let the unknown different positive integers be (a, b, c and d).

An integer is a set of element that are infinite and numeric in nature, these numbers do not contain fractions.

Suppose we make an assumption that (a) should be the greatest value of this integer.

Then, the other three positive integers (b, c and d) can be 1, 2 and 3 respectively in order to make (a) the greatest value of the integer.

Therefore, the average of this integers = 9

Mathematically;

$\mathbf{\dfrac{(a+b+c+d)}{4} =9}$

$\mathbf{\dfrac{(a+1+2+3)}{4} =9}$

$\mathbf{\dfrac{(6+a)}{4} =9}$

By cross multiplying;

6+a = 9 × 4

6+a = 36

a = 36 - 6

a = 30

Therefore, we can conclude that from the average of four positive integers which is equal to 9, the greatest value for one of the selected integers is equal to 30.

Learn more about integers here:

brainly.com/question/15276410?referrer=searchResults

Answer 2

The greatest value for one of the four positive integers is 30.

To find the largest positive integer, you have to minimize the other three positive integers.

• The least three different positive integers available = 1, 2, 3

• let the largest positive integer = y

• the sum of the four different positive integers = 1 + 2 + 3 + y = 6 + y

Find their average of the four positive integers and equate it to the given value of the average.

$\frac{6 + y}{4} = 9\\\\6+ y = 36\\\\y = 36-6\\\\y = 30$

Thus, the greatest value for one of the positive integers is 30

learn more here: brainly.com/question/20118982