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hichkok12 [17]
3 years ago
12

Simplify each sum or difference. State any restrictions on the variables.

Mathematics
1 answer:
Dvinal [7]3 years ago
7 0

Answer:

2(d-2)/(2d+1) or 1 - 5/(2d+1)

d can not be -½

Step-by-step explanation:

(d-3)/(2d+1) + (d-1)/(2d+1)

Lcm: 2d+1

(d-3+d-1)/(2d+1)

= (2d-4)/(2d+1)

= 2(d-2)/(2d+1)

If further simplification required:

= (2d-4)/(2d+1)

= (2d+1-5)/(2d+1)

= (2d+1)/(2d+1) - 5/(2d+1)

= 1 - 5/(2d+1)

2d+1 = 0

When d = -½

So d can not be -½ because when the denominator becomes 0, fraction becomes undefined

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At a hockey game, a vender sold a combined total of 176 sodas and hot dogs. The number of sodas sold was three times the number
goldfiish [28.3K]

Answer:

Hot dogs sold: 44

Sodas sold: 132

Step-by-step explanation:

This is is a problem of a system of two equations with two unknowns. This can be solved in multiple ways (the substitution method, the elimination method, the equalization method, the graphic method...) . I will resolve it using the equalization method that is a little bit more practical from my point of view.

First, we have to determine the system by the data we are given:

\left \{ {{y+x=176} \atop {y=3x}} \right.

Where:

y=sodas sold\\x=hot dogs sold

Secondly, we are going to isolate any variable from both equations. I chose to isolate Y.

\left \{ {{y=176-x} \atop {y=3x}} \right.

Thirdly, we equalizate both equations.

Y= Y

So we get:

176-x=3x

Then we isolate X.

-x-3x=-176

-4x=-176

x=-176:(-4)

x=44

So now we know that the number of hot dogs sold was 44! If the sodas sold were three times the number of hot dogs sold, then we know that there were 132 sodas sold at the hockey game!

8 0
3 years ago
What is x?<br><br> 11 + 3x = −15 − 4x
Reika [66]
11 + 3x = −15 − 4x
U subtract 11 from both sides 11+3x-11=-15-4x-11

Refine3x=-4x-26

Add 4x to both sides
3x+4x=-4x-26+4x

Refine7x=-26

Divide both sides by 7
<span>7x/7 = -26/7</span>
Refinex= -26/7
8 0
3 years ago
Jacob wants to know how many students in his school enjoy watching space travel programs on TV. He poses this question to all 20
kenny6666 [7]
The answer will be No, it is not a valid inference because his classmates do not make up a random sample of the students in the school. Hope it help!
7 0
3 years ago
Read 2 more answers
Please help!
Kobotan [32]

Answer:

You have three card : 3, 4, and 5.

You first pick one card randomly, the probability of picking a 3 is:

P = 1/3

You then pick a second card without putting the first card back, the probability of picking a 5 is:

P = 1/2

=> The probability of picking a 3 and then picking a 5:

P = (1/3) x (1/2) = 1/6

Hope this helps!

:)

8 0
3 years ago
What is the length of BC in the right triangle?
vazorg [7]
The answer is D.122 BC is the square root of 22 squared and 120 squared.
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