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2 years ago

Simplify each sum or difference. State any restrictions on the variables.

Mathematics

1 answer:

Dvinal [7]2 years ago

7 0

Answer:

2(d-2)/(2d+1) or 1 - 5/(2d+1)

d can not be -½

Step-by-step explanation:

(d-3)/(2d+1) + (d-1)/(2d+1)

Lcm: 2d+1

(d-3+d-1)/(2d+1)

= (2d-4)/(2d+1)

= 2(d-2)/(2d+1)

If further simplification required:

= (2d-4)/(2d+1)

= (2d+1-5)/(2d+1)

= (2d+1)/(2d+1) - 5/(2d+1)

= 1 - 5/(2d+1)

2d+1 = 0

When d = -½

So d can not be -½ because when the denominator becomes 0, fraction becomes undefined

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What is the solution of this proportion 4/9 = 6/d

Alchen [17]

Answer:

d = 2/27

Remember that when a variable is times with a number you <u>divide</u> the number on both sides.

When a variable is divided by a number, you <u>multiply</u> the number on both sides.

Hope this helps you and thank you !!

4 0

2 years ago

An animal feed to be mixed from soybean meal and oats must contain at least 168 lb of protein, 27 lb of fat, and 14 lb of minera

atroni [7]

Answer:

The animal farm should buy 1.775 bags of soybeans and 1.575 bags of oats

$Cost = 51.275$

Step-by-step explanation:

The given parameters can be summarized as:

$\begin{array}{cccc}{} & {x} & {y} & {Total} & {Protein} & {70} & {21} & {168} &{Fats}& {9} & {7} & {27} & {Minerals} & {7} & {1} & {14}& {Cost} & {21} & {7} & {} \ \end{array}$

Where: x = Soybeans and y = Oats.

So, the system of equations are:

$70x + 21y = 168$

$9x +7y = 27$

$7x + y = 14$

$Cost = 21x + 7y$

The best way to solve this, is using graph

Plot the following equations on a graph, and get the points of intersection:

$70x + 21y = 168$

$9x +7y = 27$

$7x + y = 14$

From the attached graph, we have:

$(x_1,y_1) = (1.636,2.545)$

$(x_2,y_2) = (1.775,1.575)$

$(x_3,y_3) = (2.023,1.256)$

Substitute each of the values of x's and y's in the cost function to get the minimum cost:

$Cost = 21x + 7y$

$(x_1,y_1) = (1.636,2.545)$

$Cost = 21 * 1.636 + 7 * 2.545$

$Cost = 52.171$

$(x_2,y_2) = (1.775,1.575)$

$Cost = 21 * 1.775 + 7 * 1.575$

$Cost = 48.3$

$(x_3,y_3) = (2.023,1.256)$

$Cost = 21 * 2.023 + 7 * 1.256$

$Cost = 51.275$

The values of x and y that gives the minimum cost is:

$(x_2,y_2) = (1.775,1.575)$

and the minimum cost is:

$Cost = 48.3$

Hence, the animal farm should buy 1.775 bags of soybeans and 1.575 bags of oats

5 0

3 years ago

Fifteen times the square of a non-zero number is equal to 15 times the number

defon

15·x²=15·x so
x²=x
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x=1

5 0

2 years ago

Read 2 more answers

Part A Assume the ball passes through the points ( 3 , 8 ) , ( 5 , 20 3 ) , and ( 6 , 5 ) . Use this data to set up a system of

Zepler [3.9K]

The three system of equations are 9a + 3b + c = 8, 75a + 15b + 3c = 20, and 36a + 6b + c = 5.

<h3>What is a solution to a system of equations? (SOLUTION GRAPHICALLY)</h3>

For a solution to be the solution to a system, it must satisfy all the equations of that system, and like all points satisfying an equation are in their graphs, so solution to a system is the intersection of all its equation at a single point(as we need a common point, which is going to be the intersection of course)(this can be one or many, or sometimes none).

The general equation of parabola is given as,

y = ax² + bx + c

The first point is (3,8), therefore, we can write,

8 = a(3)² + b(3) + c

9a + 3b + c = 8

The second point is (5, 20/3), therefore, we can write,

20/3 = a(5)² + b(5) + c

75a + 15b + 3c = 20

The third point is (6, 5), therefore, we can write,

5 = a(6)² + b(6) + c

36a + 6b + c = 5

Hence, the three system of equations are 9a + 3b + c = 8, 75a + 15b + 3c = 20, and 36a + 6b + c = 5.

Learn more about System of equations:

brainly.com/question/26254258

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How many different pizza's can be ordered if the restaurant offers 15 different toppings and there is not limit to the number of

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