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IgorC [24]
2 years ago
7

The graph of the function is of the form f(x) = a * sin(kc – c) + h.

Mathematics
1 answer:
Brut [27]2 years ago
4 0
The answer is : f(x) =3sin(2x+pi/2)

Explain

There 0,3 on the graph

You use this formula

f(x)=asin(kx-c)+h

and the maximum and minimum value of this function

a+ h and -a+ h

So a=3 and h=0

So we have

We have; f(x)= 3sin(kx - c)
and we have from the graph;

f(O)=3

So

Sin(-c) =-1

Therefore C=. Pi/ 2 +2pi n

We have period of the function is pi


2pi/ k
k=2
So it will equal Pi


Do you have any doubts ?

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Andrews [41]

Answer:

ok im not sure this is the right answer to your specific question, because i dont understand the wording to well, but here...

for 1/7 and 1/2 it would be 2/7 and 1 (whole)

for 1 and 1/7 it would be 2(whole) and 2/7

for 1 and 2/7 it would be 2(whole) and 4/7

for 4/9 it would be 8/9 and x

and for 2/9 it would be 4/9 and x

sorry if thats not the question :)

EDIT: its the second one because

2*1/7= 2/7

and 1/2*2=1

3 0
3 years ago
Read 2 more answers
Terry added 3 and 7 he got the sum of 9 his answer is is not correct described how Terry can find the correct sum
exis [7]
O it is not correct he can find the correct sum by counting and adding 8,9,10 so the answer is ten he was one of his answer he must not of counted right
5 0
3 years ago
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Solve the logarithmic equation . Round the answer to four decimal places . 2^x =25
levacccp [35]

Answer:

x = 4.6439

Step-by-step explanation:

2^x =25

Take the log of each side

log  2^x = log 25

We know that log a^b = b log a

x log 2 = log 25

Divide each side by log 2

x = log 25  / log 2

x =4.643856

Rounding to 4 decimal places

x = 4.6439

8 0
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Classify the equation 64x - 16 = 16(4x - 1) as
Maksim231197 [3]

Answer:

there is no solution 64x-16=64x-16

Step-by-step explanation:

if you distrubute then you will see the numbers are the same on both sides

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3 years ago
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Create the equation of a quadratic function with a vertex of (5,6) and a y-intercept of -69
Elena L [17]
If the y-intercept is at -69, meaning the point is (0, -69), thus x = 0, y = -69

\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
\boxed{y=a(x- h)^2+ k}\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
vertex~(5,6)\quad 
\begin{cases}
x=5\\
y=6
\end{cases}\implies y=a(x-5)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=0\\
y=-69
\end{cases}\implies -69=a(0-5)^2+6
\\\\\\
-75=25a\implies \cfrac{-75}{25}=a\implies a=-3
\\\\\\
therefore\qquad \boxed{y=-3(x-5)^2+6}
3 0
3 years ago
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