7(15) = 105
10% off means u r paying for 90%...
0.9(105) = 94.50 <=
I think the answer might be 21?
Answer:
E: (2, -1)
F: (3, -1)
G: (3, -2)
H: (2, -2)
Step-by-step explanation:
Reflect all coordinates over an x-axis
Because you are reflection 180 degrees over the x axis, the y-axis is going to stay the same (because you are not moving the square left or right. When reflecting over axis always add the same amount you took away from the other side, if that makes any sense.
Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10

10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7
