A = 0.1
B = 50.9
These are rounded to the nearest tenth
Given:
μ = 55 in, population mean
σ = 6 in, population standard deviation
Part (a)
x = 48 in, the random variable
Calculate the z-score.
z = (x - μ)/σ
= (48 - 55)/6
= -1.667
From standard table, obtain
P(X < 48) = 0.12167
Answer: 0.1217 (tyo 4 dec.places)
Answer:
The correct answer is the first one, 1 and 1/4 divided by 5/7 = ?
Step-by-step explanation:
There's not much else to it.
It's just the answer that makes the most sense.
Just use the elimination sequence.
I hope this helps!
