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andre [41]
3 years ago
8

When you are finding mode, if two numbers appear the same amount of times, do you choose the greater number or not?

Mathematics
2 answers:
Jet001 [13]3 years ago
7 0

Answer:

The number that appears the most

Step-by-step explanation:

No, you choose the number that appears the most.

(example) What is the mode of these numbers?

4,4,5,5,5,6,6

The mode would be 5 because it comes up the most

Rufina [12.5K]3 years ago
5 0

Answer:

Both of them are the mode

Step-by-step explanation:

You might be interested in
A boat can travel 16 miles up a river in 2 hours. The same boat ca travel 36 miles downstream in 3 hours. What is the speed of t
Hoochie [10]

Answer:

2 miles per hour.

Step-by-step explanation:

We want to find two things-- the speed of the boat in still water and the speed of the current.  Each of these things will be represented by a different variable:

B = speed of the boat in still water  

C = speed of the current

Since we have two variables, we will need to find a system of two equations to solve.

How do we find the two equations we need?  

Rate problems are based on the relationship Distance = (Rate)(Time).

To organize our work, we'll make a chart of the distance, rate and time that the boat travels going both upstream and downstream.  The chart will give us the information about distance, rate and time that we need to write our two equations.

Here's what the chart looks like before we put any of our information in it:  

 

 

Distance

Rate

Time

upstream

     

downstream

     

Let's look at the words of the problem.

A boat can travel 16 miles up a river in 2 hours.  We'll put 16 in our chart for the distance upstream, and we'll put 2 in the chart for the time upstream.

The same boat can travel 36 miles downstream in 3 hours.  We'll put 36 in our chart for the distance downstream, and we'll put 3 in the chart for the time downstream.

Our chart now looks like this:  

 

 

Distance

Rate

Time

upstream

16

 

2

downstream

36

 

3

Now let's think about the rate the boat travels.  We know that if the boat were on a still lake, its motor would propel it at a rate of B miles per hour.  But the boat is not on a still lake; it's moving upstream and downstream on a river.  If the boat is traveling upstream, the current (which is C miles per hour) will be pushing against the boat, and the boat's speed will decrease by C miles per hour.  The resulting speed of the boat (traveling upstream) is B-C miles per hour.  On the other hand, if the boat is traveling downstream, the current will be pushing the boat faster, and the boat's speed will increase by C miles per hour.  The resulting speed of the boat (traveling downstream) is B+C miles per hour.  We'll put this information in our chart:  

 

 

Distance

Rate

Time

upstream

16

B-C

2

downstream

36

B+C

3

Each row in the chart will give us an equation.

Going upstream, Distance = (Rate)(Time), so 16 = (B-C)(2)  

Going downstream, Distance = (Rate)(Time), so 36 = (B+C)(3)

Now we'll solve the system of equations:

16 = 2(B-C)  

36 = 3(B+C)

If we divide both sides of the first equation by 2, it will become 8 = B-C.  

If we divide both sides of the second equation by 3, it will become 12 = B+C.

We'll add these equations together to find our solution:

8  =  B-C  

12 = B+C  

20 = 2B  

10 = B

The speed of the boat in still water is 10 miles per hour.

To find the speed of the current, we can substitute 10 for the B in any of our equations.  We'll choose the easiest equation to work with:

12 = B+C  

12 = 10+C  

2 = C

The speed of the current is 2 miles per hour.  

4 0
4 years ago
What is 42 as a fraction in simplest form?
mafiozo [28]
42/1 because it's a whole number so the denominator is a 1
5 0
4 years ago
Help, if you don't know. Pls don't answer!! I need help quick!!!
fredd [130]

(y1 - y2) / (x1 - x2) = slope

(-1 - 3) / (4 - 2)

-4 / 2

<em>-2</em>

Hope this helps! :)

7 0
3 years ago
A factory produces 80,000 candies each day they produce equal quantities of for flavor cherry ,Lemon , orange , and strawberry.T
Serhud [2]

Answer:

The probably of randomly selecting an orange flavoured candy is 1/4 or 0.25

Step-by-step explanation:

Extracting the key information from the question asked:-

*** A factory produces 80,000 candies

*** Everyday of the week, they produce equal quantities of candies with varieties of flavours like cherry, lemon, orange and strawberry.

*** The candies are mixed up while packaging.

*** We are simply required to find or calculate the probability that one randomly selected candy from the pack is orange flavoured candy.

   From the question, we were informed that a particular company has the capacity of producing 80,000 candies everyday.   The company also produces these candies in four separate flavours. This now means that the number of orange candies produced will be the same as the number of strawberry candies produced and this will also be equal to the number of cherry candies produced and then the same as the number of lemon flavours made.

 That is:

Number of lemons = number of strawberries = number of cherries = number of orange flavours.

 80,000 candies are produced everyday. In order to calculate the number of equal proportions of strawberry/cherry/orange/lemon candies made per day, we will simply have to divide the total number of candies produced per day by the number of flavours available:

    = 80,000/4

    = 20,000

  Therefore, 20,000 candies of each of the four different flavours are produced by the company per day.

  Now, the probability of  randomly selecting an orange candy is

 

= the number of orange candies made per day/total number of candies produced per day

P(orange candy)

= 20,000/80,000

=  1/4

= 0.25

 The probability of randomly selecting an

orange candy is 1/4 or 0.25

4 0
4 years ago
Ericka is also in Mr. Whittaker’s science class and she recorded the variation in water level at a different part of the river.
Anton [14]

Answer:

first one is 2.2mm/year and second is 6.2years and -2.2mm/year

Step-by-step explanation:

Just trust me im right

3 0
3 years ago
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